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AQA Chemistry A2 Unit 5: Energetics, Redox and Inorganic Chemistry - 22nd June 2016

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Original post by chzm
can someone help me with this question 5b(i) to 5(b)iv its structure determinationI got the answer right when asked to deduce the structure of P, BUT my structure was the other way around, (so the same as the mark scheme if read in the opposite direction) do you get penalised for this, as i didnt see anything that said you would in the additional comments. if you do, then can someone explain to me how you know which way to draw the structure. thank you! past paper question 5biv: http://filestore.aqa.org.uk/subjects/AQA-CHEM4-QP-JAN13.PDFmark scheme: http://filestore.aqa.org.uk/subjects/AQA-CHEM4-W-MS-JAN13.PDF


This would be okay I would think, because it has the same name
Original post by woojinhyuk
Sorry. I meant why is it not called
3-Bromo-2-methylbutane


For example

Capture.JPG
Original post by chzm
can someone help me with this question 5b(i) to 5(b)iv its structure determinationI got the answer right when asked to deduce the structure of P, BUT my structure was the other way around, (so the same as the mark scheme if read in the opposite direction) do you get penalised for this, as i didnt see anything that said you would in the additional comments. if you do, then can someone explain to me how you know which way to draw the structure. thank you! past paper question 5biv: http://filestore.aqa.org.uk/subjects/AQA-CHEM4-QP-JAN13.PDFmark scheme: http://filestore.aqa.org.uk/subjects/AQA-CHEM4-W-MS-JAN13.PDF


No need to worry.

image.jpeg
Original post by TeachChemistry
Substituents in alphabetical order (as you have done) then lowest numbers assigned overall in order. If you do it the other way round in an exam I doubt you'd be penalised.


Thanks but I still don't understand why
2-Bromo-3-methylbutane is correct. In the textbook it says to number it so that the highest priority group is the lowest number (which in this case is the alkyl group). Maybe I'm missing something or just confused lol
Original post by woojinhyuk
Thanks but I still don't understand why
2-Bromo-3-methylbutane is correct. In the textbook it says to number it so that the highest priority group is the lowest number (which in this case is the alkyl group). Maybe I'm missing something or just confused lol


Read these links

https://chemlaba.wordpress.com/2011/03/12/iupac-nomenclature-of-alkyl-halides/

http://www.chem.uiuc.edu/GenChemReferences/nomenclature_rules.html

The names I gave above for three examples were generated using a chemical drawing package with IUPAC naming software incorporated into it.
Original post by TeachChemistry
Read these links

https://chemlaba.wordpress.com/2011/03/12/iupac-nomenclature-of-alkyl-halides/

http://www.chem.uiuc.edu/GenChemReferences/nomenclature_rules.html

The names I gave above for three examples were generated using a chemical drawing package with IUPAC naming software incorporated into it.


These links are quite helpful. Thanks for the help.
Reply 26
Original post by Larashax
image.png

Here you go 😊

Please, do you have page 158 also ?
(edited 7 years ago)
Reply 27
Original post by chzm
how do you know when to include the platinium electrode in cell representations?


When the two species are of the same state or do not conduct electricity on their own.e.g. fe2+ions and fe3+ ions and then the standard hydrogen gas but also could potentially be helium gas but i doubt they would bring that up in an example
I thought Cr3+ and [Cr(H2O)6]3+ are the same thing. But they have different colors? So what's going on?
Reply 29
I know it's too late but could someone please help me with this? :3

Why is it not B?
@TeachChemistry please or anyone else?
Reply 30
Original post by Aimen.
I know it's too late but could someone please help me with this? :3

Why is it not B?
@TeachChemistry please or anyone else?


The answer was D right?, I would personally guess that the H2SO4 may not fully dissociate and would only dissociate into HSO4- so the concentration of H+ isn't quite 1 mol dm-3!
Original post by Aimen.
I know it's too late but could someone please help me with this? :3

Why is it not B?
@TeachChemistry please or anyone else?


Hey,

It's D because one atmospheric pressure is equal to about 100 kPa

Hope it helps
Original post by Aimen.
I know it's too late but could someone please help me with this? :3

Why is it not B?
@TeachChemistry please or anyone else?



STANDARD (therefore has to be in standard conditions) Hydrogen electrode; ONE mole, and 100KPa (aka about 1atm)
B is saying in 0.5 mol... not one mol hence its incorrect :smile:
How did you guys find the paper?!
Reply 34
It was good and better than unit 4
Reply 35
One of the easiest ive done, much easier than chem 4
I thought it ws ok:smile:
Did any one get 94.4% for percentage purity
Original post by Maligaha
Did any one get 94.4% for percentage purity


I got 64.7% 🙈
Reply 39
Thought it was a pretty standard paper, much much better tha unit 4 ahaha :/
Calculaions that i remember are
Latt dis: 2328
Delta h sol: -155
Delta h: -196
Delta s: -189 jmol^-1
Delta g: -135
Substance x i got as P
Amphoteric substance al2o3
Weakest oxidising agent is zn2+ i think
Copper contain compound cu2+
H2->2H+ +2e-
2h2o+o2+4e-->4oh-
Dunnon if i remeber much else im guessing 80-83ish for A?? But then again we can only guess
(edited 7 years ago)

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