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mei FP2 complex numbers topic assessment question

I've been working through the end of unit assessment for FP2 Complex Numbers & I'm completely stuck on 3(b)(ii)

This is the question:

Snapchat-8828170094255374979.jpg

And this is what I have so far



any help is appreciated (especially if I have made a mistake in my working so far)

Thanks!
Original post by wamble

any help is appreciated (especially if I have made a mistake in my working so far)

Thanks!


So, you've gotten to tan2θsec6θ\dfrac{\tan^2\theta}{\sec^6 \theta}

I'd convert to sines and cosines, and simplify and see how you can use part (b)(i) of the question - which I can't see clearly in the photo.
Reply 2
Original post by wamble


Thanks!


Oh and tan2θ+1=sec2θ    tan2θ=sec2θ11sec2θ\tan^2 \theta + 1 = \sec^2 \theta \iff \tan^2 \theta = \sec^2 \theta - 1 \neq 1 - \sec^2 \theta
Original post by wamble
I've been working through the end of unit assessment for FP2 Complex Numbers & I'm completely stuck on 3(b)(ii)

This is the question:



any help is appreciated (especially if I have made a mistake in my working so far)

Thanks!


tan2x(1+tan2x)4sec2x=tan2x(1+tan2x)4(1+tan2x)=tan2x(sec2x)3\frac{\tan^2 x}{(1+\tan^2 x)^4} \sec^2 x = \frac{\tan^2 x}{(1+\tan^2 x)^4} (1+\tan^2 x) = \frac{\tan^2 x}{(\sec^2 x)^3}

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