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Reply 1
kriztinae
hey can anyone help me last minute"? im sure its easy i jut dont know how to do it!
nyway they want you to find the integral of x+1/ (9x^2 -16)^1/2

before that they asked you to find the integral of 1/ (9x^2 -16)^1/2
can anyone help me?


The bottom one's a formula book one, take out a factor of 3 (root 9) on the bottom line and compare with the standard one in the formula book.

The top one, split into two fractions, the x/(9x² - 16)^1/2 you use a substitution of u = 9x² - 16 and the other fraction is the first one which you do the way I said above.
Reply 2
Giraffeboy
The bottom one's a formula book one, take out a factor of 3 (root 9) on the bottom line and compare with the standard one in the formula book.

The top one, split into two fractions, the x/(9x² - 16)^1/2 you use a substitution of u = 9x² - 16 and the other fraction is the first one which you do the way I said above.

thanx!! i love you! your a life saver!!

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