Completing the square

Hi,

Please could someone help me understand why 3/4 +/- 1/4(√33) = 1/4(3 +/- √33).

I just don't get it!

Thanks

Original post by talkingbiology

Hi,

Please could someone help me understand why 3/4 +/- 1/4(√33) = 1/4(3 +/- √33).

I just don't get it!

Thanks

\frac{3}{4} \pm \frac{\sqrt{33}}{4}= \frac{3 \pm \sqrt{33}}{4} = \frac{1}{4}(3 \pm \sqrt{33})

\frac{3}{4} \pm \frac{\sqrt{33}}{4}= \frac{3 \pm \sqrt{33}}{4} = \frac{1}{4}(3 \pm \sqrt{33})

Cheers!

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