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Additional maths fsmq question

The equation where x^3 - 3x + k = 0, where k is a constant, has a root x=2.

Find the numerical value(s) of the other roots of this equation.

*any help would be much appreciated :smile:*
Reply 1
Original post by machau
The equation where x^3 - 3x + k = 0, where k is a constant, has a root x=2.

Find the numerical value(s) of the other roots of this equation.

*any help would be much appreciated :smile:*

sub x=2 into the equation to find k, then factorize as
(x-2)*quadratic
And solve for the roots of the quadratic.
Reply 2
Original post by mqb2766
sub x=2 into the equation to find k, then factorize as
(x-2)*quadratic
And solve for the roots of the quadratic.

Thanks, that makes sense 😊
(edited 4 years ago)
Reply 3
Original post by machau
Thanks, but how do I find the quadratic?

Either do polynomial division or write it as
ax^2 + bx + c
And multiply by (x-2) and equate to the cubic.
Reply 4
Original post by mqb2766
Either do polynomial division or write it as
ax^2 + bx + c
And multiply by (x-2) and equate to the cubic.

Okay, thanks :smile:

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