Please can you send an image of the graph and tunnel?
Original post by the bear
Original post by bobbbobb
Here is a sketch of the graph of y = 9 – x^2
The graph is used to model the cross section of a tunnel.
The unshaded area is the cross section of the tunnel.
Calculate an estimate of the area of the cross section of the tunnel.
The graph is used to model the cross section of a tunnel.
The unshaded area is the cross section of the tunnel.
Calculate an estimate of the area of the cross section of the tunnel.
Treat the 3 sections as triangles and rectangles as it says to estimate the area of the cross sectional area not find its exact value
(edited 11 months ago)
First, you need to find the area of the curve. Seperate the curve into trapeziums, as done between -1 and -2 on the x axis. Then find the area of these and add them up. Then, find the area of the whole graph. This is sum(x) * sum(y), so here it would be 9*10 = 90. Do area of graph - area of curve to find the area of the cross-section.
Hope this helps.
Hope this helps.
Original post by bobbbobb
Ok thank you, I got 45 is that right?
I got 57...
I got 30 lmao
@bobbbobb do you have a mark scheme or a correct answer?
Apparently, the answer is 35 (page 16) 
Yeah, I see where I went wrong. I forgot to include the two 0 values in the trap rule.
To get the right answer you need to use the trapezium rule, adding up the areas of each trapezium.
This gets you to 35. I can explain more if you need
To get the right answer you need to use the trapezium rule, adding up the areas of each trapezium.
This gets you to 35. I can explain more if you need
Original post by pinkrocket
Yeah, I see where I went wrong. I forgot to include the two 0 values in the trap rule.
To get the right answer you need to use the trapezium rule, adding up the areas of each trapezium.
This gets you to 35. I can explain more if you need
To get the right answer you need to use the trapezium rule, adding up the areas of each trapezium.
This gets you to 35. I can explain more if you need
Same, my maths was just a bit off
Original post by taylor2317
Same, my maths was just a bit off
Im blaming it on the fact its 10pm. Too tired for maths atm
Thank you, I understand how you got 35, what do you do after please?
Original post by taylor2317
Same, my maths was just a bit off
Original post by bobbbobb
Thank you, I understand how you got 35, what do you do after please?
If you got 35, then that's the final answer because the question asked for the unshaded area, which is what you've found with the trapezium rule.
Original post by bobbbobb
Thank you, I understand how you got 35, what do you do after please?
35 is the correct answer; that's it!
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