Hi there,
I would like to help in this:
Tackling the task, let's use the following variables:
r = the amount of red wine
w = the amount of white wine
c = the amount of corked wine
d = the amount of drinkable wine
We are given the following information:
d = 6c
dr = 8cw
dw = 5cw
Substituting the first equation into the second equation, we get:
8cw = 5cw
This means that there is 8/5 times as much drinkable red wine as corked white wine.
Substituting the first equation into the third equation, we get:
6c = 5cw
This means there is 6/5 times as much drinkable white wine as corked red wine.
Since the amount of drinkable red wine is equal to the amount of corked white wine, we can set these two equations equal to each other:
8cw = 6c
This gives us c = 8/6 = 4/3
We can now solve for the total amount of red and white wine:
r + w = c + d = 4/3 + 6/3 = 10/3
The ratio of red wine to white wine is:
r/w = (4/3) / (6/3) = 2/3
Therefore, the red and white wine ratio in your cellar is 2:3.
Hope I have answered your task
Thank you.