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A level Maths OCR question help

I am doing a question where I have to prove that 5(x^2-2)(4x+9)^1/2 can be written as k(5x^2+9x-2)/(4x+9)^1/2 where k is a constant

my problem is that the equation they want me to prove looks like quotient rule but the first equation isn't a fraction...if that makes sense
Reply 1
Original post by esha06
I am doing a question where I have to prove that 5(x^2-2)(4x+9)^1/2 can be written as k(5x^2+9x-2)/(4x+9)^1/2 where k is a constant

my problem is that the equation they want me to prove looks like quotient rule but the first equation isn't a fraction...if that makes sense

Its a product so differentiate using that rule.
Reply 2
Original post by mqb2766
Its a product so differentiate using that rule.

but if i do that i wont get (4x+9)^1/2 as the denominator
Reply 3
Original post by esha06
but if i do that i wont get (4x+9)^1/2 as the denominator

Guess youve not tried it? Derivative of 2x^(1/2) is 1/x^(1/2)
Reply 4
Original post by mqb2766
Guess youve not tried it? Derivative of 2x^(1/2) is 1/x^(1/2)

i dont mean to be stupid but where are u getting 2x^1/2 from
Reply 5
Original post by esha06
i dont mean to be stupid but where are u getting 2x^1/2 from

Just a simple example. Just try using the product rule and see how it goes.
Reply 6
Original post by mqb2766
Just a simple example. Just try using the product rule and see how it goes.

i tried product rule and got 5x^3+70/3x^2+20x-20/3😭😭
Reply 7
Original post by esha06
i tried product rule and got 5x^3+70/3x^2+20x-20/3😭😭

Youll have to show your working, as thats obviously wrong.
Reply 8
Original post by mqb2766
Youll have to show your working, as thats obviously wrong.



i’ve probably made a stupid mistake tbh
Reply 9
Original post by esha06


i’ve probably made a stupid mistake tbh

Cant see the image unfortunately, image uploading has been even more flakey after the recent upgrades.
Reply 10
Original post by mqb2766
Cant see the image unfortunately, image uploading has been even more flakey after the recent upgrades.

Reply 11
Original post by esha06

WHen you evaulate v' you seem to forget that its (4x+9)^(-1/2) on the second line of working. Thats the reason you get a sqrt(4x+9) on the deonominator.
Reply 12
Original post by mqb2766
WHen you evaulate v' you seem to forget that its (4x+9)^(-1/2) on the second line of working. Thats the reason you get a sqrt(4x+9) on the deonominator.

so i have to use quotient rule inside of product rule basically?
Reply 13
Original post by esha06
so i have to use quotient rule inside of product rule basically?

No. The quotient rule is a special case of the product rule, but here you use the product rule properly. Here you have
v = (4x+9)^(1/2)
v' = 2 (4x+9)^(-1/2) = 2/(4x+9)^(1/2)
(edited 4 months ago)
Reply 14
Original post by mqb2766
No. Firstly, the quotient rule is a special case of the product rule, but here you use the product rule properly. Here you have
v = (4x+9)^(1/2)
v' = 2 (4x+9)^(-1/2) = 2/(4x+9)^(1/2)

ohhhhh i get ittt thank you so much!

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