PC2 Maths, AQA 24/05/10

And the answers: to which I hope you're all very grateful as it's taken me ages to find all the right symbols on microsoft word, and re-do the paper haha

hey rob, I think some of your answers may be wrong for question 8, mainly the translation of the graph question and the x co-ordinate Q.

I think Q = 0 and i think the translation is (2^4x-1)-0.5

I cant read the answers..lol
anyway what did u get for question 4c?

Hey rob, not sure if your answer for question 8c is correct, but nevertheless thanks for the paper and answers! So disappointed for not getting 3b... I got 18.5 degrees, so would I get one method mark for that?

If your answers are right, then i have only dropped about 7-8 marks and now feel less depressed

It was more difficult to work out that angle, so I'm guessing it will be considered as a mis-read and you'll only drop 1 mark for that, but I'm not an examiner (:

(8c) is certainly correct, however I'm in the minority who got it right so a lot of people on here will tell you otherwise, however after convincing my maths teachers, we've agreed that the answer is a translation of 0.75 units

Here they are:

Any chance that is because there is 4x?

How on earth did you get that? Did your school give you a copy?

I'll try exporting it into different formats also?

4c) -1.7

Hi Rob.. thanks for the upload, brilliant help.

I'm so confused though over the trap rule question.. the values you've subbed into the formula remind me of mine but I'm sure I got the X values wrong - what were the X values?

where they 0, 0.2, 0.4, 06 etc...

wow now I'm remembering myself rubbing my whole question out after using 7 ordinantes and doing it again... ahh I best forget it otherwise it'l ldrive me crazy...

Hi Rob.. thanks for the upload, brilliant help.

I'm so confused though over the trap rule question.. the values you've subbed into the formula remind me of mine but I'm sure I got the X values wrong - what were the X values?

where they 0, 0.2, 0.4, 06 etc...

wow now I'm remembering myself rubbing my whole question out after using 7 ordinantes and doing it again... ahh I best forget it otherwise it'l ldrive me crazy...

There are four lot of "x", if you translate each "x" 3 unit to the right. The graph would move 12 unit......

Hope this make sense (which it doesnt)

-.- , I'm still adament i'm right on this, consider this.

y=x^2

F(X) =X^2 agreed?

F(X-2) = (X+2)^2

Now by your argument, you would argue that it aught to be the root of 2, am I correct? because the square of 2 is 4, meaning a translation of 4 not too. But this is wrong. I wil explain.

Say we have the graph (X+2)^2, now w/e this you want this graph to look like, imagine now we do a horizontal stretch paralell to the x axis of 1/2. Now this function should look like, [2(x+2)]^2. However if this is so, surely you would say, the graph would be translated more so, as the +2 is now multiplied. But this is silly.

Now if your still not convinced, I have scoured youtube for a decent video which supports my point, (there were alot).

http://www.youtube.com/watch?v=cPiBh1TEHfk&feature=related

Are you now happy that the translation of the graph IS [3,0]. If not PLEASE explain because I'd like to know if you have anything more to contribute.

All the best, Ollie.

-.- , I'm still adament i'm right on this, consider this.

Hey Rob... do you suppose I'll lose marks on the integral as my final answer was positive 1.7, I clearly stated prior to that that the value was -1.7, then proceeded to write 1.7 square units to round it off. What do you reckon?