Assume that we have this alcohol: (CH3)3COH. In this case, we will have three methyl functional groups on the only C.
Now, and I know that the formula may be wrong, but just want to ask if we see a formula like the following, on which C will the CH3 be located, the first C (from the left), or the second one?
Assume that we have this alcohol: (CH3)3COH. In this case, we will have three methyl functional groups on the only C.
Now, and I know that the formula may be wrong, but just want to ask if we see a formula like the following, on which C will the CH3 be located, the first C (from the left), or the second one?
CH(CH3)3COH
Thanks.
That's an impossible compund. You have a Texas carbon! Try drawing it, and you'll see