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OCR M1 - 31st May 2012 :)

Haven't seen one of these for this exam... post the M1 problems up on here for OCR ...
:smile:

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I'm doing M1 also at this time :biggrin:

It is by far the most difficult out of the 4 units I am doing this summer IMO (m1,s1,d1,c2) because I find it hard to understand what the question is actually asking for, and some of the latter examples are very complicated :/

I have no questions I am doing that I am stuck on at the moment, but GL on your revision! :smile:
Reply 2
Original post by Genesis2703
I'm doing M1 also at this time :biggrin:

It is by far the most difficult out of the 4 units I am doing this summer IMO (m1,s1,d1,c2) because I find it hard to understand what the question is actually asking for, and some of the latter examples are very complicated :/

I have no questions I am doing that I am stuck on at the moment, but GL on your revision! :smile:


Post it up.. lets try and solve it :smile:
Reply 3
How would I solve this question guys?



I get a = 39.2 ms^-2 and T = 147 N but they don't seem right...
Reply 4
Original post by PeterStoba
How would I solve this question guys?



I get a = 39.2 ms^-2 and T = 147 N but they don't seem right...




I got a = 2.45m/s/s
AND t = 36.75N

Whats the answer??
Reply 5
Original post by Smiley Face :)
I got a = 2.45m/s/s
AND t = 36.75N

Whats the answer??


I also get the same answers.
Reply 6
Original post by raheem94
I also get the same answers.


Wooop! First time my answers match with u boss :smile:
Reply 7
I do not know, the mark scheme is unavailable. I know my answer is wrong.

What method did you use?
Reply 8
Original post by PeterStoba
I do not know, the mark scheme is unavailable. I know my answer is wrong.

What method did you use?


See the diagram in the spoiler:

Spoiler



Now form 2 equations,
First consider the 5kg particle, 5gT=5a(1) 5g-T=5a \longrightarrow (1)

Now consider the 3kg particle, T3g=3a(2) T-3g=3a \longrightarrow (2)

Now solve (1)  and  (2) (1) \ \ and \ \ (2) simultaneously.
(edited 11 years ago)
Reply 9
I don't see where 7 has came from here? But...

Equation 1 x3, 15g - 21 = 15a
Equation 2 x5, 5T - 15g = 15a

15g - 21 = 5T - 15g
(30g - 21) / 5 = T
T = 54.6?

I must be missing something?
Peter, the 7 was meant to be a T. I think Raheem made a typing error.

Try it again with 5g - T = 5a instead of with a 7 :smile:
Reply 11
Haha I look like an idiot now! I was honestly confused as to where 7 came from.

Right so now I get the correct answers! Thanks everyone :-)
Reply 12
Original post by PeterStoba
I don't see where 7 has came from here? But...

Equation 1 x3, 15g - 21 = 15a
Equation 2 x5, 5T - 15g = 15a

15g - 21 = 5T - 15g
(30g - 21) / 5 = T
T = 54.6?

I must be missing something?


Sorry, it was a typo.

Original post by Genesis2703
Peter, the 7 was meant to be a T. I think Raheem made a typing error.

Try it again with 5g - T = 5a instead of with a 7 :smile:


Thanks for clearing the doubt.
Original post by PeterStoba
Haha I look like an idiot now! I was honestly confused as to where 7 came from.

Right so now I get the correct answers! Thanks everyone :-)


haha Don't worry about it man! :smile:

Oh and in class we went over an m1 paper we did for HW/in class, and I got 100%.. but I feel bad because Of course I asked for help on the harder questions, and struggle a lot when left alone. I feel like I am giving the teacher the wrong impression tbh :frown: (It was the Jan 2011 paper btw)
Reply 14
Just let him know you got some help on a few of the questions and you don't feel you'd get 100% on your own / another paper?

I think you are all doing OCR? I'm MEI, just realised!

Anything about calculating trajectory etc on your spec?
Original post by PeterStoba
Just let him know you got some help on a few of the questions and you don't feel you'd get 100% on your own / another paper?

I think you are all doing OCR? I'm MEI, just realised!

Anything about calculating trajectory etc on your spec?


Unless you mean angle of the resultant force then no I do not think OCR covers that in M1. You could post a question and see if we know though... but I think we will not understand it :P
Reply 16
Original post by Smiley Face :)
Haven't seen one of these for this exam... post the M1 problems up on here for OCR ...
:smile:



Original post by Genesis2703
I'm doing M1 also at this time :biggrin:

It is by far the most difficult out of the 4 units I am doing this summer IMO (m1,s1,d1,c2) because I find it hard to understand what the question is actually asking for, and some of the latter examples are very complicated :/

I have no questions I am doing that I am stuck on at the moment, but GL on your revision! :smile:



Original post by raheem94
I also get the same answers.


hi guys im also doing this paper. i have a quick question; are we allowed to use this formula for tension - T=mg+ma ? thanks a lot.
Reply 17
Original post by ugk4life
hi guys im also doing this paper. i have a quick question; are we allowed to use this formula for tension - T=mg+ma ? thanks a lot.


You have to form the equation by considering the situation, there isn't a general formula which will apply to all situations.

Always draw a diagram and resolve the forces, to get the equations.

And by the way, i am not doing this exam.
Reply 18
Original post by raheem94
You have to form the equation by considering the situation, there isn't a general formula which will apply to all situations.

Always draw a diagram and resolve the forces, to get the equations.

And by the way, i am not doing this exam.


ok thanks, my friend told me this formula so i was wondering if this can apply to all situations.

guess ill have to stick with drawing the diagrams and stuff lol.
Original post by raheem94
I also get the same answers.


Hey, Could u helpme out please.
http://www.ocr.org.uk/download/pp_11_jun/ocr_66474_pp_11_jun_gce_4728.pdf

June 11
Q2 part 4
I have got that P will further go up by 0.036 M. I then added this to the 0.36M to get 0.396M.. In order to get the greastest height of P
However the markscheme has said that the greatest height of P is 0.756 M
I don't understand how and why they have got that value...

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