\displaystyle \sum_{n=0}^{\infty}\left [(n+1)(n+2) a_{n+2} - a_n] x^n=\sum_{n=0}^{\infty}\left [(-1)^{n+1}\frac{x^{n+1}}{(2n+1)!}] x^n
\displaystyle \sum_{n=0}^{\infty}\left [(n+1)(n+2) a_{n+2} - a_n] x^n=\sum_{n=0}^{\infty}\left [(-1)^{n+1}\frac{x^{n+1}}{(2n+1)!}] x^n
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Did Cambridge maths students find maths and further maths a level very easy?Last reply 2 weeks ago
Edexcel A Level Mathematics Paper 2 unofficial mark scheme correct me if wrong71
Last reply 4 days ago
Did Cambridge maths students find maths and further maths a level very easy?Last reply 2 weeks ago
Edexcel A Level Mathematics Paper 2 unofficial mark scheme correct me if wrong71