This discussion is now closed.

Check out other Related discussions

OCR Chemistry F322~ 4th June 2013~ AS Chemistry

Enthalpy change of reaction is the molar quanities...there was only one mole in the equation so you would of had to divide 1/0.005 which is 200 then 200 x 7.06 = 1412

Anyone else or just me lol...

Yeah that's right haha, or you could have just done 7.06/0.005 :smile:

Same thing.

Reply 3401

joe1545

14

Original post by Lysipud

Enthalpy change of reaction is the molar quanities...there was only one mole in the equation so you would of had to divide 1/0.005 which is 200 then 200 x 7.06 = 1412

Anyone else or just me lol...

What you done is exactly the same as dividing by 0.005

Reply 3402

Greasy Gorilla

What doe you think the boundaries for the grades will be?

Reply 3403

nothepreacher

18

Original post by anon_69

I think the delta H was for 2 moles of NO2 therefore 10/2(240/24) * 164 is how i did it.

thats wrong it was +164, the equation given was N2 + 0.5 O2 ----> N2O

Reply 3404

Kenna

Original post by TheGeneral95

Did the paper require a signature ?

Posted from TSR Mobile

Nope, only AQA do I think.

Reply 3405

reneetaylor

11

Original post by the A* guy

The uploader on TSR is not working, so i managed to get the first 5 pages on to a PDF on a website domain. Bear with the link, it might take a while to load.

Rest of the pages to follow soon.

http://examwizard.yolasite.com/resources/Scan-12.pdf

Hope it helps!

Thank you for your time!

Reply 3406

such

5

What did everyone put for the two functional groups in the really long ester (compound I)?

Reply 3407

nothepreacher

18

Original post by such

That's the same as dividing 7.06 by 0.005 directly. I got 1412 kJ mol^-1 too.

Did you put a negative sign though?

Reply 3408

joe1545

14

Original post by 344302

Why was a yellow flame and black smoke ..

Was it incomplete combustion??

Posted from TSR Mobile

Yea i said the black smoke shows the production of CO, which means their is a lack of oxygen hence the organic substance I is undergoing incomplete combustion

Reply 3409

yodawg321

12

What did people get for "Suggest why there are a large number of products formed from cracking?"

Reply 3410

Europa192

Original post by niceguy95

For G did people get C5H9O

I think I got C5H9O, maybe you forgot the hydrogen in the OH group? Not sure :/

Reply 3411

such

5

Original post by nothepreacher

thats wrong it was +164, the equation given was N2 + 0.5 O2 ----> N2O

The equation was 2N₂ + O₂ --> 2N₂O. I think the answer was +164/2 = +82

Reply 3412

Gotzz

13

Original post by such

That's the same as dividing 7.06 by 0.005 directly. I got 1412 kJ mol^-1 too.

Me too! Then put the minus sign.

Reply 3413

Kat12395

1

Original post by Lysipud

Hmm I said because CO2 gas is being produced. Reacon I'll get a mark for that?

I put this too, although I was guessing most of it! This paper was nothing like anything I've ever done I hated it:L

Posted from TSR Mobile

Reply 3414

joe1545

14

Original post by yodawg321

Dont you have to say because it was the only product formed?

OHH YEA sheeet... i forgot it was the polymerisation, and H2 isnt produced... Ahh sillly me

Reply 3415

Hawthorns

Original post by the A* guy

The uploader on TSR is not working, so i managed to get the first 5 pages on to a PDF on a website domain. Bear with the link, it might take a while to load.

Rest of the pages to follow soon.

http://examwizard.yolasite.com/resources/Scan-12.pdf

Hope it helps!

Thankyou! When will the rest be up?