Can you help me with a chemistry question?
http://www.ocr.org.uk/Images/144862-question-paper-unit-a172-01-modules-c4-c5-c6-higher-tier.pdf
Page 12 I don't get it. I've looked at the mark scheme but still no help. Please help.Thanks.
Page 12 I don't get it. I've looked at the mark scheme but still no help. Please help.Thanks.
I don't do ocr but from what I've read for first question it's just the Mr of copper(2) divided by the Mr of the whole compound times by 100....so the Mr of copper is (63.5*2) divided by the Mr of the whole compound (63.5*2)+32 and times by 100 this gets you 79.9%..rounded. Is this correct?
Original post by JazzyT17
http://www.ocr.org.uk/Images/144862-question-paper-unit-a172-01-modules-c4-c5-c6-higher-tier.pdf
Page 12 I don't get it. I've looked at the mark scheme but still no help. Please help.Thanks.
Page 12 I don't get it. I've looked at the mark scheme but still no help. Please help.Thanks.
Original post by GS98
I don't do ocr but from what I've read for first question it's just the Mr of copper(2) divided by the Mr of the whole compound times by 100....so the Mr of copper is (63.5*2) divided by the Mr of the whole compound (63.5*2)+32 and times by 100 this gets you 79.9%..rounded. Is this correct?
Ar of coppper in the molecule divded by Mr of Cu2S and then multiply that by 100.
(edited 10 years ago)
Original post by JazzyT17
http://www.ocr.org.uk/Images/144862-question-paper-unit-a172-01-modules-c4-c5-c6-higher-tier.pdf
Page 12 I don't get it. I've looked at the mark scheme but still no help. Please help.Thanks.
Page 12 I don't get it. I've looked at the mark scheme but still no help. Please help.Thanks.
do you have the link ot the mark scheme
because i hav an idea of how to do it, just want to check!thanks
i guess fro part aii you just multitply the percentage by 1kg, to give 0.798kg of cu ?
Original post by GS98
It's copper with a little 2 so it wouldn't be the Ar, it would be the Mr?
ar is 63.5 mr is 127
Original post by zhzstudent
do you have the link ot the mark scheme
because i hav an idea of how to do it, just want to check!thanks
because i hav an idea of how to do it, just want to check!thanks
http://www.ocr.org.uk/Images/142598-mark-scheme-unit-a172-02-chemistry-modules-c4-c5-c6-higher-january.pdf
yep i was right, you just times the percentage with the 1kg to get0.799 kg
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