So my Maths teacher set us homework. It's Percentage profit/loss. In class the only example she gave us was a grid. In the textbook it has equations she didn't specify how we should set it out so i'm confused T_T
So my Maths teacher set us homework. It's Percentage profit/loss. In class the only example she gave us was a grid. In the textbook it has equations she didn't specify how we should set it out so i'm confused T_T
Cool I know these equations how do u want me to help u? do u want me to tell u how to balance equations Do u want me to help u in maths too as u mentioned in ur previous post??
Some of these are displacement reactions. Just swap the cations in each compound. This is just balancing equations. The number of each type of atom on the left side of the equation has to equal the number of that type of atoms on the right. Some of the questions involve electrons, in which case you use the same rules, also with the number of electrons on the left equals the number of electrons on the right.
Have u heard that mass is neither created nor destroyed. Use this to balance equations equation: H2SO4+NaOH-----Na2SO4+H20 so we balance this by considering I element at a time so the first one is H see before the reaction there are 3 atoms of H but after the reaction there are only 2 which means it is not balance. We balance this by adding 2 in front of H20 so this is going to be 2H20. Then for S there is 1 atom before the reaction and 1 atom after the reaction which means it is balance. Now O as u can see there are 5 atoms of O before the reaction but after the reaction they turned to 6 because we added 2 in front of H20 which means that there are 2 atoms of O present in this compound. Now as for Na there is one atom before the reaction but after the reaction there are 2 atoms so you simply write 2 in front of NaOH making it 2NaOH. So the equation is going to be H2SO4+2NaOH----Na2SO4+2H2O
I used this equation from the pic u send me of ur textbook. Anything else?
Have u heard that mass is neither created nor destroyed.
According to relativity, mass is created and destroyed all the time. In this case, you would use the principle that an atom can't change elements within a purely chemical reaction.
According to relativity, mass is created and destroyed all the time. In this case, you would use the principle that an atom can't change elements within a purely chemical reaction.
The rest of it is correct.
Isn't it the conversation of mass where it say mass can neither be created nor destroyed. I might be wrong but can u explain how plz?
Isn't it the conversation of mass where it say mass can neither be created nor destroyed. I might be wrong but can u explain how plz?
Sorry I meant the mass associated with matter could change, in the context of chemical reactions. Mass itself can't be destroyed. An atom/molecule with greater bonds but the same particles will have less mass.
Why do you add two to the H? When you can add one??
Because there are more atoms of H on the left than on the right. You add the two in an attempt to balance it. The job isn't complete at that stage though, because there are now more H on the right than the left.
Why do you add two to the H? When you can add one??
No u cant add 1 u knw if i put 2 infront of H20 to make it 2H2O this means that the big 2 is multiplying by the small 2 it means H have 4 atoms as 2*2 is 4. U dont put 1 cuz multiplying by 1 won't work
Sorry I meant the mass associated with matter could change, in the context of chemical reactions. Mass itself can't be destroyed. An atom/molecule with greater bonds but the same particles will have less mass.
An atom/molecule with greater bonds but the same particles will have less mass. I don't get this sorry
Thank you so much!! The textbook doesn't expain stuff that good. I like things simplified. I think I should try some myself. There are more stuff but I don't wanna waste your time again thanks for the help
An atom/molecule with greater bonds but the same particles will have less mass. I don't get this sorry
When the particles are arranged in a way where they have bonds, the molecule will have a smaller potential energy than when the particles are separate. Energy is given off when bonds are formed. As E=mc2, the particles will also have a smaller mass.
Thank you so much!! The textbook doesn't expain stuff that good. I like things simplified. I think I should try some myself. There are more stuff but I don't wanna waste your time again thanks for the help
I have time u can ask me more glad I could help u nad make sense to u
When the particles are arranged in a way where they have bonds, the molecule will have a smaller potential energy than when the particles are separate. Energy is given off when bonds are formed. As E=mc2, the particles will also have a smaller mass.
You don't need to know this.
Yeah I haven't learned this yet may be next year thanks for explaining though