Current Year 13 thread Mark I (2014-2015)

Sorry to bother everyone but I'm stuck again... Please help? I've tried it by parts again but it's looking quite messy... I really can't integrate!! :frown:

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Reply 7582

Dexterous

14

Original post by Princepieman

Absolutely loved watching lewis break down like that, he puts on this facade but really he's just a softie.

Posted from TSR Mobile

Yeah like a teddy bear

Original post by binarythoughts

The cliffhanger could've been better, the whole Mike and Rachel thing was sweet though

No way, he gave death stares to everyone but his PA and the other partners :K:

The death stare :rofl:

Original post by Obiejess

Spoilers guys. Some of us are still on Season 2!

Posted from TSR Mobile

Oops, lips are sealed!

Reply 7583

L'Evil Fish

Original post by strawberrysnow

Sorry to bother everyone but I'm stuck again... Please help? I've tried it by parts again but it's looking quite messy... I really can't integrate!! :frown:

Same thing as last one

Differentiate (x³+1)^(3/2)

Reply 7584

Original post by L'Evil Fish

Same thing as last one

Differentiate (x³+1)^(3/2)

Thank you so much! :biggrin:

I feel like an idiot... I'm just so bad at integrating!

But how did you know to differentiate it to the power of 3/2? I realised it was similar to the last question, but I just didn't know what to put instead of the 1/2, if you know what I mean?

(edited 9 years ago)

Reply 7585

Original post by pryngles

I JUST GOT AN OFFER OR REJECTION EMAIL BUT BECAUSE UCAS IS DOWN I HAVE TO WAIT UNTIL MONDAY THIS IS HELL :frown:

apapapiwjepfla alckenspabxkspemflalabckfnaiallcbdoalabxbcocoeuhwosjdvoenaoancifos

Track is back up! What was the outcome?

Reply 7586

Original post by strawberrysnow

C4 integration:

Please can someone help me integrate this? I've tried integrating it by parts but I just get left with this huge mess :frown:

thanks!

Integration by substitution
u = x^3
That way you can get rid of the x^2 when you do du/dx
Good luck and tell me when you solve it :smile:

Reply 7587

L'Evil Fish

Original post by strawberrysnow

Thank you so much! :biggrin:

I feel like an idiot... I'm just so bad at integrating!

But how did you know to differentiate it to the power of 3/2? I realised it was similar to the last question, but I just didn't know what to put instead of the 1/2, if you know what I mean?

Add 1 to the power

By chain rule you take one from the power so you do the opposite

Original post by The Clockwork Apple

Integration by substitution
u = x^3
That way you can get rid of the x^2 when you do du/dx
Good luck and tell me when you solve it :smile:

Could do this as well

Reply 7588

Original post by The Clockwork Apple

Integration by substitution
u = x^3
That way you can get rid of the x^2 when you do du/dx
Good luck and tell me when you solve it :smile:

Thank you - I kind of understand what you're talking about :smile:

I'm still confused though - I'm just awful at integrating! Can you please explain further? I'm really sorry... :frown:

Reply 7589

L'Evil Fish

Original post by strawberrysnow

Thank you - I kind of understand what you're talking about :smile:

I'm still confused though - I'm just awful at integrating! Can you please explain further? I'm really sorry... :frown:

Just do it my way

Reply 7590

Original post by L'Evil Fish

Just do it my way

Haha, yes thank you!! :biggrin:

Reply 7591

Original post by strawberrysnow

Thank you - I kind of understand what you're talking about :smile:

I'm still confused though - I'm just awful at integrating! Can you please explain further? I'm really sorry... :frown:

Sure! I'm in a car journey rn (I'll be home in like 3 hours), so I can send you a complete solution when I get home.

Reply 7592

Original post by strawberrysnow

Haha, yes thank you!! :biggrin:

In any case, if you subs u = x^3, you'll get an overall equation:
(u-2)^7 which should be very easy to integrate!
If you don't know how to get to (u-2)^7 tell me where you get lost and I'll get into more detail

Reply 7593

Original post by The Clockwork Apple

In any case, if you subs u = x^3, you'll get an overall equation:
(u-2)^7 which should be very easy to integrate!
If you don't know how to get to (u-2)^7 tell me where you get lost and I'll get into more detail

Thank you so much for your kindness :smile:

I've got (u-2)^8 / 8 now, but I'm still not sure what to do from there... ><

I'm really sorry for making you explain to me.. I'm really bad at integrating :frown:

Reply 7594

rachelc142

11

Original post by strawberrysnow

Sorry to bother everyone but I'm stuck again... Please help? I've tried it by parts again but it's looking quite messy... I really can't integrate!! :frown:

I think you might be doing exactly the same exercise as me xD is it exc 10.9 page 246/247? :tongue:

Reply 7595

Original post by rachelc142

i think you might be doing exactly the same exercise as me xd is it exc 10.9 page 246/247? :tongue:

posted from tsr mobile

YES ohmygosh can we do these exercises together?? :biggrin:

Reply 7596

rachelc142

11

Original post by strawberrysnow

YES ohmygosh can we do these exercises together?? :biggrin:

I'm on Q15 so can help you up to there :tongue:

Reply 7597

Original post by rachelc142

I'm on Q15 so can help you up to there :tongue:

OMG wow! I've done questions 1-9 so far, apart from question 7 - could you please help me with that? Also, can you please help me with question 10? :tongue:

(edited 9 years ago)

Reply 7598

binarythoughts

14

Math mock was a joke today

Reply 7599