Rate equation
In each of the following questions, use the initial rate data to find:
1) the order with respect to each reactant and the total (overall) order
2)the rate equation
3) the rate constant k (including its units) at the experiments temperature.
b) the reaction between iodine and propanone is catalysed by H+ ions
Experiment 1 = Initial [H+] in mol dm ^-3 is 0.5
initial[propanone] in mol dm^-3 is 6
initial [I2] in mol dm^-3 is 0.02
initial rate mol dm^-3 s^-1 is 9.0 * 10^-5
Experiment 2 = Initial [H+] is 0.5
Initial [Propanone] is 6
Initial I2 is 0.04
Initial Rate is 9.0 * 10^-5
Experiment 3 = Initial H+ is 1.0
Initial Propanone is 6
Initial [I2] is 0.02
Initial rate is 1.8 * 10^-4
Experiment 4= Initial [H+] is 1.0
Initial [propanone] is 8
Initial [I2] is 0.02
Initial rate is 2.4 * 10^-4
1c) D reacts with E to form various products.
Experiment 1= Initial[ D] in mol dm^-3 is 1
Initial [E] in mol dm^-3 is 1
Initial rate in mol dm^-3s^-1 is 0.20
Experiment 2= Initial [D] is 2
Initial [E] is 1
Initial rate is 0.20
Experiment 3 =Initial [D] is 4
Initial [E] is 4
Initial rate is 0.80
1) the order with respect to each reactant and the total (overall) order
2)the rate equation
3) the rate constant k (including its units) at the experiments temperature.
b) the reaction between iodine and propanone is catalysed by H+ ions
Experiment 1 = Initial [H+] in mol dm ^-3 is 0.5
initial[propanone] in mol dm^-3 is 6
initial [I2] in mol dm^-3 is 0.02
initial rate mol dm^-3 s^-1 is 9.0 * 10^-5
Experiment 2 = Initial [H+] is 0.5
Initial [Propanone] is 6
Initial I2 is 0.04
Initial Rate is 9.0 * 10^-5
Experiment 3 = Initial H+ is 1.0
Initial Propanone is 6
Initial [I2] is 0.02
Initial rate is 1.8 * 10^-4
Experiment 4= Initial [H+] is 1.0
Initial [propanone] is 8
Initial [I2] is 0.02
Initial rate is 2.4 * 10^-4
1c) D reacts with E to form various products.
Experiment 1= Initial[ D] in mol dm^-3 is 1
Initial [E] in mol dm^-3 is 1
Initial rate in mol dm^-3s^-1 is 0.20
Experiment 2= Initial [D] is 2
Initial [E] is 1
Initial rate is 0.20
Experiment 3 =Initial [D] is 4
Initial [E] is 4
Initial rate is 0.80
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Spoiler
Original post by Pigster
How far have you got?
I'm not quite sure how to do it
Original post by Jyotii
In each of the following questions, use the initial rate data to find:
1) the order with respect to each reactant and the total (overall) order
2)the rate equation
3) the rate constant k (including its units) at the experiments temperature.
b) the reaction between iodine and propanone is catalysed by H+ ions
Experiment 1 = Initial [H+] in mol dm ^-3 is 0.5
initial[propanone] in mol dm^-3 is 6
initial [I2] in mol dm^-3 is 0.02
initial rate mol dm^-3 s^-1 is 9.0 * 10^-5
Experiment 2 = Initial [H+] is 0.5
Initial [Propanone] is 6
Initial I2 is 0.04
Initial Rate is 9.0 * 10^-5
Experiment 3 = Initial H+ is 1.0
Initial Propanone is 6
Initial [I2] is 0.02
Initial rate is 1.8 * 10^-4
Experiment 4= Initial [H+] is 1.0
Initial [propanone] is 8
Initial [I2] is 0.02
Initial rate is 2.4 * 10^-4
1c) D reacts with E to form various products.
Experiment 1= Initial[ D] in mol dm^-3 is 1
Initial [E] in mol dm^-3 is 1
Initial rate in mol dm^-3s^-1 is 0.20
Experiment 2= Initial [D] is 2
Initial [E] is 1
Initial rate is 0.20
Experiment 3 =Initial [D] is 4
Initial [E] is 4
Initial rate is 0.80
1) the order with respect to each reactant and the total (overall) order
2)the rate equation
3) the rate constant k (including its units) at the experiments temperature.
b) the reaction between iodine and propanone is catalysed by H+ ions
Experiment 1 = Initial [H+] in mol dm ^-3 is 0.5
initial[propanone] in mol dm^-3 is 6
initial [I2] in mol dm^-3 is 0.02
initial rate mol dm^-3 s^-1 is 9.0 * 10^-5
Experiment 2 = Initial [H+] is 0.5
Initial [Propanone] is 6
Initial I2 is 0.04
Initial Rate is 9.0 * 10^-5
Experiment 3 = Initial H+ is 1.0
Initial Propanone is 6
Initial [I2] is 0.02
Initial rate is 1.8 * 10^-4
Experiment 4= Initial [H+] is 1.0
Initial [propanone] is 8
Initial [I2] is 0.02
Initial rate is 2.4 * 10^-4
1c) D reacts with E to form various products.
Experiment 1= Initial[ D] in mol dm^-3 is 1
Initial [E] in mol dm^-3 is 1
Initial rate in mol dm^-3s^-1 is 0.20
Experiment 2= Initial [D] is 2
Initial [E] is 1
Initial rate is 0.20
Experiment 3 =Initial [D] is 4
Initial [E] is 4
Initial rate is 0.80
Here is an interactive on solving the rate equation. Read through it carefully and you will understand how to solve the problem
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