\displaystyle[br]\begin{equation*}\int_{\frac{-1}{4}}^{\frac{1}{6}} \frac{8x + 12}{\sqrt{4x^2 + 12x + 5}} \, \mathrm{d}x + \int_{\frac{-1}{4}}^{\frac{1}{6}}\frac{1 \, \mathrm{d}x}{\sqrt{4x^2 + 12x + 5}} = \int_{\frac{-1}{4}}^{\frac{1}{6}} \frac{(4x^2 + 12x+5)'}{\sqrt{4x^2 + 12x+5}} \, \mathrm{d}x + \int_{\frac{-1}{4}}^{\frac{1}{6}} \frac{1}{\sqrt{4x^2 + 12x + 5}}} \, \mathrm{d}x \end{equation*}
\displaystyle[br]\begin{equation*}\int_{\frac{-1}{4}}^{\frac{1}{6}} \frac{8x + 12}{\sqrt{4x^2 + 12x + 5}} \, \mathrm{d}x + \int_{\frac{-1}{4}}^{\frac{1}{6}}\frac{1 \, \mathrm{d}x}{\sqrt{4x^2 + 12x + 5}} = \int_{\frac{-1}{4}}^{\frac{1}{6}} \frac{(4x^2 + 12x+5)'}{\sqrt{4x^2 + 12x+5}} \, \mathrm{d}x + \int_{\frac{-1}{4}}^{\frac{1}{6}} \frac{1}{\sqrt{4x^2 + 12x + 5}}} \, \mathrm{d}x \end{equation*}
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