Year 12s: what will be the first way you research your future options? >>

Year 12s: what will be the first way you research your future options? >>

Year 12s: what will be the first way you research your future options? >>

C2 QUESTION HELP needed!

Could somebody give me a STEP BY STEP working out of how to do this answer.

Thanks in advance!

OP

I know that! I'm talking about part b! :biggrin:

:biggrin:

really? it's obvious right?

i seem to get 11:22am as a time before midday, i can't find any others though :/

@Zacken

OP

Apparently, the answer is = 0623, 1137. (The mark scheme says it will allow both radians or degrees, but i used radians).

Original post by greentron6

Apparently, the answer is = 0623, 1137. (The mark scheme says it will allow both radians or degrees, but i used radians).

\frac{\pi T}{6} = \sin^{-1} \frac{1}{5}, \frac{\pi}{2} - \sin^{-1} \frac{1}{5}

OP

Original post by Zacken

\frac{\pi T}{6} = \sin^{-1} \frac{1}{5}, \frac{\pi}{2} - \sin^{-1} \frac{1}{5}

Could you actually give me a step by step explanation of how and why you got the answer?

Original post by greentron6

Could you actually give me a step by step explanation of how and why you got the answer?

What don't you understand about it? What have you tried?

OP

Original post by Zacken

What don't you understand about it? What have you tried?

Yes, I tried it and I treated it as a trigonometric equation, however something went wrong after that. That's why was I want a step by step explanation, so I can identify my mistake.

Original post by greentron6

Yes, I tried it and I treated it as a trigonometric equation, however something went wrong after that. That's why was I want a step by step explanation, so I can identify my mistake.

Post what you've tried and we'll identify your mistake for you.

OP

Original post by Zacken

Post what you've tried and we'll identify your mistake for you.

20160521_170520[1].jpg

Original post by greentron6

20160521_170520[1].jpg

Everything up to

\frac{\pi T}{6} = \sin^{-1}\left( -\frac{1}{5}\right)

This has several solutions:

\frac{\pi T}{6} = -0.201

\frac{\pi T}{6} = \pi - - 0.201

\frac{\pi T}{6} = -0.201 + 2\pi

This gives (ignoring the negative solutions because time is positive):

T = 3.684

and I'll let you do the other one. But 6.384 hours is 6 hours and 23 minutes after midnight.

Can you do the other solution?

(edited 7 years ago)

OP

Original post by Zacken

Everything up to

\frac{\pi T}{6} = \sin^{-1}\left( -\frac{1}{5}\right)

This has several solutions:

\frac{\pi T}{6} = -0.201

\frac{\pi T}{6} = \pi - - 0.201

\frac{\pi T}{6} = -0.201 + 2\pi

This gives (ignoring the negative solutions because time is positive):

T = 6.684

and I'll let you do the other one. But 6.384 hours is 6 hours and 23 minutes after midnight.

Can you do the other solution?

Yes, thank you very much!

Original post by greentron6

Yes, thank you very much!

No problem.

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