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DNA sequencing? Sanger method?

Can someone please tell me the key points in this method? I am really confused
Sorry you've not had any responses about this. :frown: Are you sure you've posted in the right place? :smile: Here's a link to our subject forum which should help get you more responses if you post there. :redface:

You can also find the Exam Thread list for A-levels here and GCSE here. :dumbells:


Just quoting in Puddles the Monkey so she can move the thread if needed :h:

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Reply 2
You have a sequence of bases that you want to read. This is your template.
You use a primer that always binds to the same region. This is your starting point
You then have premature termination of chain elongation by the polymerase because you attach a nucleotide that is not capable of binding to another nucleotide.
In each step you only have these special nucleotides being of one type only, I.e. Either G, T, C or A. Let's assume you just have G.
In the mix though, you have normal G nucleotides that can bind to other nucleotides as well. So whether it terminates at a G or not is purely up to luck.
Since your starting point of the polymerase is always the same, the shortest fragment is your starting "position", as this is the earliest possible place of G.
You repeat for all the nucleotides, and then you compare the sizes of the fragments, with the shortest one being the starting position.


copied and pasted from another post of mine here!
Reply 3
Original post by alkyone
You have a sequence of bases that you want to read. This is your template.
You use a primer that always binds to the same region. This is your starting point
You then have premature termination of chain elongation by the polymerase because you attach a nucleotide that is not capable of binding to another nucleotide.
In each step you only have these special nucleotides being of one type only, I.e. Either G, T, C or A. Let's assume you just have G.
In the mix though, you have normal G nucleotides that can bind to other nucleotides as well. So whether it terminates at a G or not is purely up to luck.
Since your starting point of the polymerase is always the same, the shortest fragment is your starting "position", as this is the earliest possible place of G.
You repeat for all the nucleotides, and then you compare the sizes of the fragments, with the shortest one being the starting position.


copied and pasted from another post of mine here!


thank you so much!

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