Official OCR A2 G484 June 2016 [Module 1] [90UMS]

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Reply 260

Will127

Original post by AmashQamar97

Anyone with realistic predictions on the grade boundaries?

I think they'll be low, purely because it was a wierd paper

Reply 261

BriO

If you hold a pipe pumping water upward which way will you be pushed? Downward. So the reaction force is weight +sin55*force exerted by pipe. What did everyone get for maxiumum velocity of the oscillating system?

Reply 262

steph-carys

Original post by AlistairMcDonald

struggling to remember, but I think i did basically the opposite curve to the epe one, crossing the epe one at 40, with a max of 50

I got the same as you for the phase diff one too :frown:

Okay, cause I drew my stationary point for KE at the max EPE point, and one girl in my class drew KE sitting along the x axis and this has puzzled me :/

And that's somewhat nice to hear ahaha... I went over that phase question again and again and I was feeling pretty confident about it :frown:

Reply 263

seanthubb

Original post by steph-carys

How did you folks draw the KE/EPE graph? Differences of opinion at school

Inverted version of the potential energy graph, max at the same height as potential but when the potential is at a minimum. Starts and ends at same displacements.

Reply 264

screwedmofo

Original post by AmashQamar97

Anyone with realistic predictions on the grade boundaries?

The june 2014 paper was the hardest paper of this series , grade boundaries were 39 for A,

In my opinion this paper felt harder, but i think its 39/40/41 for an A.

Reply 265

thephysio

Original post by AmashQamar97

Anyone with realistic predictions on the grade boundaries?

Predictions
90UMS - 50 marks

80UMS - 46 marks

70UMS - 41 marks

(edited 7 years ago)

Reply 266

TheFarmerLad

Original post by amashqamar97

anyone with realistic predictions on the grade boundaries?

52 - 100
48 - a*
44 - a
40 - b
37 - c

Reply 267

BongoBuddha

How many marks do you think the boltzmann factor questions were worth in total (i left these blank) :s-smilie:

Reply 268

balmdog

Original post by AmashQamar97

Anyone with realistic predictions on the grade boundaries?

Based on the boundaries of june 2014 which was considered a hard exam, the A mark could drop as low as 39, so i'd say

A-42
B-38
C-34
D-30
E-26

Reply 269

Jm098

Do they ecf? I written the max KE was 80 not 50 to calculate Vmax?

Reply 270

tobybes

Original post by tobybes

Ok so ita probably not that helpful, I have the numerical answers I got.
5.78
3.45
0.61 m
1072 N
5pi/4
0.471
0.666 (Hz or s)
Masses 1.2 and 3.6 X 10^whatsits
Mass of star : 6.41 X 10^31 kg
0.925
23300
59800
1.03x10^33 (can't remember the question haha)
130.8 (shc)
489
11300mol

Hoping that 90UMS is around 55. Paper 5 is horrific.

Also,I think:
CAP - 52
A* - 47
A - 42

Reply 271

steph-carys

Original post by Asiimov

Inverted version of the potential energy graph, max at the same height as potential but when the potential is at a minimum. Starts and ends at same displacements.

Damn, I botched up my graph then. Hopefully there will be full ecf for following calculations..

Reply 272

joeteeeeee

Original post by TheFarmerLad

52 - 100
48 - a*
44 - a
40 - b
37 - c

Are u retarded last years exam was much easier and was 43 for an a u spaz

Reply 273

Danny_L

Original post by Jm098

Do they ecf? I written the max KE was 80 not 50 to calculate Vmax?

Same fmll. Was going for 100% umsd
too. Think I may miss out now

Reply 274

Jm098

Original post by Danny_L

Same fmll. Was going for 100% umsd
too. Think I may miss out now

Its actually so annoying isn't it haha now I realise why the boundaries are so low, so many silly mistakes

Reply 275

UnknownAnon

Anyone else absolutely hate that exam? Had a mini panic attack during it. Just gonna find a way to sell my soul for an A haha

Reply 276

steph-carys

Original post by Danny_L

Same fmll. Was going for 100% umsd
too. Think I may miss out now

Hey same here! :frown:

Plus I messed up the mass of S2... and the hose question...

Reply 277

yuweizheng

F=(-GM1M2)/(R1+R2)^2
F1=4pi^2M1R1/T^2
R1=1.2times10^12
R2=3.6times same power
To find velocity use v=2piR/T
I can't remember the exact answer but if process is correct the answer should be right as well.