I can't remember the question but i thought it asked something like the difference in force between x and y so whats the difference between closest point on the circle but isn't it the same because anywhere on a circle has the same distance from the centre and therefore the same force.

Reply 1869

blt12

Original post by perpetua

But D is no reciprocal either, as it touches both axes

F= EQ - E is constant anf Q is constant, so surely F is constant?

Reply 1870

marioman

8

Original post by study.bud

Sorry but no actually, F=EQ and E=V/d so F=VQ/d. So it would have been the reciprocal graph. The electric field strength is constant, not the force

The answer was definitely the graph showing constant force.

Reply 1871

tanyapotter

20

Original post by Ginpls

Cyber abuse TANYA POTTER

i will literally kill you gin

Reply 1872

NVismvlol

1

Original post by Squishy•

I can't remember the question but i thought it asked something like the difference in force between x and y so whats the difference between closest point on the circle but isn't it the same because anywhere on a circle has the same distance from the centre and therefore the same force.

It was the force between X and Y and you had to use Pythagoras to solve it, resulting in an answer of 3F

Reply 1873

sandisiwe

1

Original post by tanyapotter

i will literally kill you gin

...............................

Reply 1874

Vikingninja

21

For the 2nd last multiple choice with the train through the magnetic field did anyone get C?

Original post by Yo12345

For the electromagnetic brakeI put:Advantage: A bigger brake force can be applied by making the magnetic field strongerDisadvantage: The brake would heat moreAre any of these right?Posted from TSR Mobile

Yeah you could potentially get a larger brake force if you have a rather powerful electromagnetic. Disadvantage not sure, with a high resistance and current to get the high brake force the coil could heat up more.

Reply 1875

Yo12345

2

Original post by Vikingninja

For the 2nd last multiple choice with the train through the magnetic field did anyone get C?

Yeah you could potentially get a larger brake force if you have a rather powerful electromagnetic. Disadvantage not sure, with a high resistance and current to get the high brake force the coil could heat up more.

Thank you for replying :smile:

Posted from TSR Mobile

Reply 1876

-jordan-

5

Original post by marioman

The answer was definitely the graph showing constant force.

There is a question is one of the past papers which asks you to find the force between two parallel points at the midpoint. Of course it's QV/D but most chose distractor QV/2D. The force is the same at all points between plates, it is uniform. So yeah it is.

Reply 1877

Vikingninja

21

Original post by liverpool2044

why did i get 11 farads for the capacitance, i did q/v and worked out the gradient, surely i wont lose 3 or will there be a range of answers

What points did you use on the graph? Since it was gradient I did the differences between two points. I got 8 micro farads.

Reply 1878

aelahi23

2

For Section B the first question about finding the capacitance of the capacitor the gradient from the graph would have given 1/C
right?

I think I got 8 farads for that question I tried to find the gradient of the line then just used the reciprocal of the found gradient which got me 8 farads

Please tell me if i did it correctly

Reply 1879

Vikingninja

21

Original post by aelahi23

For Section B the first question about finding the capacitance of the capacitor the gradient from the graph would have given 1/C
right?

I think I got 8 farads for that question I tried to find the gradient of the line then just used the reciprocal of the found gradient which got me 8 farads

It was micro farads but if you put the number 8 as the answer it was right because the symbol was micro farads. The gradient was C because it was Q/V, I got 8 micro farads from doing the gradient.

AQA Physics PHYA4 - 20th June 2016 [Exam Discussion Thread]

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