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Edexcel Core 3 - 21st June 2016 AM

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where the **** is arsey im having a meltdown
Reply 1581
Original post by mangoli
I used long division + factor theorum, although now i've seen it partial fractions would've been easier


Original post by Yua
did you remainder end up like so

4x+12

4(x+3)/(x+3)(x-2)

so 4/x-2

????
Reply 1582
Original post by Iamvery1/cos(c)
My sister just sat this exam and she realised afterwards that she completely missed out the last question because she didn't see it.

Will this be catastrophic if she wants a high A?

not if everything else was right
Original post by jwanjwan
where the **** is arsey im having a meltdown


He doesn't do model answers anymore
Original post by Yua
am i the only one that didn't use partial fractions?


Nope I just did it the core 3 way, divided, got a remainder, put that over the original fraction, factorised top and bottom and cancelled.
Original post by blahblah21
Q1a, x=6, x=-5
b. a=6
2a. dy/dx = (20-4x^2)/(x^2+5)^2
b. x>rt(5) x<-rt(5)
3a. rt(5)cos(theta +26.57)
b. theta = 33.0, 273.9
c. theta = 86.1
4a. y=21, x=ln(2.5)
y=25 (k=25)
b. Proof
c. x1= 1.4368
x2= 1.4373
d. Show the change in sign. (gradient function)
5i. Turning points: 0.9463
ii. 0.5cosec(4y)
6a. A=3 B=4
b. x+2y-35=0 (or equivalent)
7a. arcsin(x) graph
b. x= -(2+rt(3))/2
8a. Proof
b. x= 0.294, -1.277, 1.865 and 1 more I think
9a. 6.740
b. Proof
c. T = 5ln(2+(2/e))


5 ii was 2cosec4y I think
Original post by mangoli
I used long division + factor theorum, although now i've seen it partial fractions would've been easier


To be fair long division is remarkably quick for this question in particular.

The remainder was nice and cancelled down into the form required beautifully.
Original post by Yua
am i the only one that didn't use partial fractions?


nope, i used polynomial division
how many marks was Q9?
x4+x3−3x2+7x−6x2+x−6=x2+x−6


Anyone got the Algebraic Fraction method for me please?
I have never been taught long division, and I know I got the answers wrong, just looking to see if I got some method marks.
Can anybody remember how much was question 1 a) worth?


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Original post by Anon-
how did you show that it was the right root to 3 decimal places using an appropriate interval?


g(x) - (2(x)+43) with the appropriate x values will get you a change of sign
Original post by AhnafR
Guys which equation did you substitute in the values to get the sign change to prove x=1.473?


It was g(x) - (what g(x) was = to in that part)
So the one with the es minus the one that was ax+b...
That was probably useless sorry, but you might know what I mean? x
b + b/e = [7.5/(15e^-1 + 15)]^-1

(be+b)/e = [7.5/(15e^-1 + 15)]^-1

be+b = [7.5/(15e^-1 + 15)]^-1 * e

b(e+1) = [7.5/(15e^-1 + 15)]^-1 * e

b = [7.5/(15e^-1 + 15)]^-1 * e / e + 1

b = 2

(This looks horrible but LaTeX doesn't seem to be working, sorry)
(edited 7 years ago)
Original post by Yua
did you remainder end up like so

4x+12

4(x+3)/(x+3)(x-2)

so 4/x-2


mate are we the same person? exactly what I did, long division, then my remainder cancelled it exactly like that you boss lad
How Many Marks was Q9?
Can anyone tell me what kind of time we could expect a 'model answers' unofficial mark scheme? Where they show all the working out etc? Are they normally on the day or the day after?
Original post by mpwb12345
Will send u it


Hi could you send it to me too please?
Original post by TheBillPN
Yeah ive seen the answers i want the method, i got it completely wrong as far as i can tell


Here is my working. I may have written the original question down wrong because I worked backwards from the answer to get the question. I'm fairly certain the first factor you had to take out was (x+3) but I could be wrong. Either way after I cancel that factor off top and bottom it is definitely correct.

Spoiler

(edited 7 years ago)
Original post by jwanjwan
where the **** is arsey im having a meltdown


He's not doing them anymore, Edexcel told him to stop.

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