Standing waves-Physics
A loudspeaker points directly at a wall 3m away. It emits a wave of frequency 680Hz and a standing wave is formed.
Is this the correct way to work this out?
v=fλ
340/680=λ
λ=1/2
λ=2L - I'm assuming this is the frist harmonic, even though it doesnt state. Is this normal?
L=0.5/2
L=0.25
Is this the correct way to work this out?
v=fλ
340/680=λ
λ=1/2
λ=2L - I'm assuming this is the frist harmonic, even though it doesnt state. Is this normal?
L=0.5/2
L=0.25
If it is first harmonic, the length of the string is 2 times the wavelength. Therefore L = 2λ, L/2 = λ. Now sub in ya values so L = ?.
Original post by assassinjeev22
If it is first harmonic, the length of the string is 2 times the wavelength. Therefore L = 2λ, L/2 = λ. Now sub in ya values so L = ?.
shouldn't it be λ=2L and L=λ/2
Original post by joyoustele
shouldn't it be λ=2L and L=λ/2
Oh yeah sorry got abit muddled up there my apologies
Other than that yeah all seems good but they usually do state if its first harmonic(aka fundamental frequency), 2nd harmonic etc.
(edited 6 years ago)
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