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Natural Logarithms

Struggling with Q6. Any help would be appreciated. I'll post the question and my method in a moment. :smile:
Original post by Emsio8
Struggling with Q6. Any help would be appreciated. I'll post the question and my method in a moment. :smile:


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Original post by Emsio8
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Line 3 is wrong.

Begin by saying that 3xe4x1=53xe4x=5e3^xe^{4x-1} = 5 \Leftrightarrow 3^x e^{4x} = 5e then note that the LHS is just (3e4)x(3e^4)^x

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