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Maths questionn

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I am not too sure what to do here?
Reply 1
Do you know what the implies arrows mean with the directions?

Let's say P is 'It is daytime' and Q is 'We can see the Sun'

Then Q ==> P because we can't see the Sun at night. P ==> Q is not true, because it can be daytime but too cloudy to see the Sun. If both directions were true, you can then write P <==>Q.
Reply 2
Original post by ThomH97
Do you know what the implies arrows mean with the directions?

Let's say P is 'It is daytime' and Q is 'We can see the Sun'

Then Q ==> P because we can't see the Sun at night. P ==> Q is not true, because it can be daytime but too cloudy to see the Sun. If both directions were true, you can then write P <==>Q.

Isn't it if and only if?
so for Q ==> P , it means Q is true if and only if P is true

I am struggling with the first question though
Reply 3
Original post by Kalabamboo
Isn't it if and only if?
so for Q ==> P , it means Q is true if and only if P is true

I am struggling with the first question though


But if and only if means it's a two way implication. So for question 1, if x=1, does x²+x-2=0? And if x²+x-2=0, does x=1? Your answer to each question will tell you what you need to know
Reply 4
Original post by MR1999
But if and only if means it's a two way implication. So for question 1, if x=1, does x²+x-2=0? And if x²+x-2=0, does x=1? Your answer to each question will tell you what you need to know


Doesn't it work both ways?
Reply 5
Original post by Kalabamboo
Isn't it if and only if?
so for Q ==> P , it means Q is true if and only if P is true

I am struggling with the first question though


'If and only if' (or 'iff' for short if your lecturer is cool with that) is <==>. This means that if either is true, then the other must be true as well.

Q ==> P reads as 'Q implies P', so if Q is true, then P must also be true. You can also read Q ==> P as 'if Q is true, then P is true'.

'It is snowing' ==> 'It is cold', for example, but the other way round isn't true.
Reply 6
Original post by ThomH97
'If and only if' (or 'iff' for short if your lecturer is cool with that) is <==>. This means that if either is true, then the other must be true as well.

Q ==> P reads as 'Q implies P', so if Q is true, then P must also be true. You can also read Q ==> P as 'if Q is true, then P is true'.

'It is snowing' ==> 'It is cold', for example, but the other way round isn't true.


Ah ok so for the first question, would it go both ways?
Reply 7
Original post by Kalabamboo
Ah ok so for the first question, would it go both ways?


Can you start from P and get to Q, with nothing extra?

If x^2 = 9, is it definitely true that x = -3?
Reply 8
Original post by ThomH97
Can you start from P and get to Q, with nothing extra?

If x^2 = 9, is it definitely true that x = -3?

Sure, the example you've given makes sense as x could instead= 3. However I am not really sure how it is related to the question here.
Reply 9
Original post by Kalabamboo
Sure, the example you've given makes sense as x could instead= 3. However I am not really sure how it is related to the question here.


Indeed, x could be +3 instead. So you can't say that x^2 = 9 implies (means) that x = -3 because it could be +3. But it is true that x = -3 implies x^2 = 9 so we can write x = -3 ==> x = 9.
Original post by ThomH97
Indeed, x could be +3 instead. So you can't say that x^2 = 9 implies (means) that x = -3 because it could be +3. But it is true that x = -3 implies x^2 = 9 so we can write x = -3 ==> x = 9.


Thanks a lot! For part ii) in the ms it says both of them implies each other - I don't quite understand this. Could you please kindly help with this?
Ik it's quite late right now so no worries if not possible :smile:
Original post by Kalabamboo
Thanks a lot! For part ii) in the ms it says both of them implies each other - I don't quite understand this. Could you please kindly help with this?
Ik it's quite late right now so no worries if not possible :smile:


Q ==> P is pretty straightforward. For P ==> Q, you're trying to say that if y^3 > 1, then y has to be greater than 1. Can you think of a way for that to be false?

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