OCR A: AS Further Mathematics: Statistics (paper 2) 16th May 2019

Cool. I misstepped in the last question by thinking that only adjacent positions could switch so instead of the probability being (nc2 + 1)/n! I got (n)/n!, which led to a result of 6 instead of 7 but the rest of the method was exactly the same. Do you think that will still get any marks?

Cool. I misstepped in the last question by thinking that only adjacent positions could switch so instead of the probability being (nc2 + 1)/n! I got (n)/n!, which led to a result of 6 instead of 7 but the rest of the method was exactly the same. Do you think that will still get any marks?

Does anyone remember a question early on where it was like spearman’s rank < 1 and there were 9 rankings. did the question ask for the smallest possible value of spearman’s rank or largest — I think I did the opposite?

Also - for like Q1, was anyone else wondering why the expectation was worth 1 mark but the variance was worth 2 marks? I thought I had missed something...?

Does anyone remember a question early on where it was like spearman’s rank < 1 and there were 9 rankings. did the question ask for the smallest possible value of spearman’s rank or largest — I think I did the opposite?

Also - for like Q1, was anyone else wondering why the expectation was worth 1 mark but the variance was worth 2 marks? I thought I had missed something...?

I think it was largest spearman's under 1. I hope so anyway as that's what I did

Same here. Did you get something like 0.983 or similar?

Same here. Did you get something like 0.983 or similar?

Yeah I think so but I did write it down in the last second

Same here. Did you get something like 0.983 or similar?

59/60 is 0.98333.... though?

Yeah but we were told to round it to either 3 sf or 4 sf, if you didn't round it and just wrote a long answer like 0.98333333 they can take away marks for not rounding. Either giving the exact fraction or 3 sf would be fine though

I put it to 3sf but yeah 59/60 is definitely that value either way - okay this paper didn’t go as bad as I initially felt so I’m glad

What distribution did people use for the beads question?

So what does everyone estimate for the Stats boundaries for an A?

I reckon it will be between 41-43 for an A, so similar to last year's boundaries.

You think? I think it'll be higher. It was much easier than the pure and I don't see that boundary being lower than 40. Also I I found it easier than the 2018 paper think it'll be 45-48, similar to last year's core paper(47)

The question is what the grade boundaries for the pure will be? I totally messed that one up. I think it'll be 32-just a bit lower than last year's mechanics.