logarithms question help

https://activeteach-prod.resource.pearson-intl.com/r00/r0066/r006621/r00662150/current/alevelsb_p1_ex14h.pdf

For question 6c, wouldn't the y-intercept (logA) be 3.69? Where did they get 3.76 from?

The points are not all exactly on a straight line. They have taken the intercept from an attempted line of best fit through (or past) all the points rather than from the single point (0, 3.69).

I see, would it be wrong if I used the point (0, 3.69) rather than from the straight line? If I used 3.69, A would be 4900, which is 900 less than the official answer. Should I be using the straight line from now on instead of the single point?

I see, would it be wrong if I used the point (0, 3.69) rather than from the straight line? If I used 3.69, A would be 4900, which is 900 less than the official answer. Should I be using the straight line from now on instead of the single point?

Linear regression gives an intercept of 3.76.

Strangely the solution bank says "reading the intercept from the graph" and they don't seem to have done this.

It's usually best to use the line of best fit rather than a single point.

My textbook also says "reading the intercept from the graph" in the examples given. I haven't done linear interpolation in a very long while D:

Oh, that was your textbook, I thought it was the solution bank. This would be linear regression rather than interpolation. Finding the line of best fit by linear regression is no longer in the syllabus. As old_engineer says, using the line of best fit is best in these cases as you're using all the data rather than just one point.