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What's the answer?/how do I do this? (algebraic manipulation)

Reply 1

As per your other post, what have you tried?
With a bit of factorization, pythagorean identity, its not that bad.
(edited 2 years ago)
Original post by mqb2766
As per your other post, what have you tried?
With a bit of factorization, pythagorean identity, its not that bad.

20220109_141644.jpg
Original post by mqb2766
As per your other post, what have you tried?
With a bit of factorization, pythagorean identity, its not that bad.

That's what I've done, I don't know how you would eliminate the 2 more terms, or how this could simplify any further. The site gives you options to use tan( ), but I don't see where sin/tan would come up
Original post by mqb2766
As per your other post, what have you tried?
With a bit of factorization, pythagorean identity, its not that bad.

On the last line, the squared sign should be applied to only the (ccos(x)-v), not the whole thing, I just wrote it out wrong
Reply 5
Original post by Jordan Inglis
That's what I've done, I don't know how you would eliminate the 2 more terms, or how this could simplify any further. The site gives you options to use tan( ), but I don't see where sin/tan would come up

ok, on the top you;ve got the chance of a sin^2 and a cos^2 which should simplify?
Original post by mqb2766
ok, on the top you;ve got the chance of a sin^2 and a cos^2 which should simplify?

20220109_150908.jpg. I did that and simplified it to c^2. I don't know enough about trig identities to know what else cancels
Reply 7
Just use the same identity again for
-sin^2 = cos^2 - 1
which should get you there.
Original post by mqb2766
Just use the same identity again for
-sin^2 = cos^2 - 1
which should get you there.

Yeah, I got the answer, tysm!

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