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    (Original post by Zacken)
    As above - (I have no clue how this slipped my eye) but the correct answer should be \frac{5(1 - \sqrt{2})}{-1} = \frac{5 - 5\sqrt{2}}{-1} = 5\sqrt{2} - 5, i.e: you need to multiply out the 5(1-\sqrt{2}) as 5 - 5\sqrt{2} and not as 5 - \sqrt{2}.
    Phewww, so I was right!
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    (Original post by phat-chewbacca)
    Phewww, so I was right!
    Yeah, just me being dumb again :lol:
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    (Original post by Zacken)
    Yeah, just me being dumb again :lol:
    It happens to everyone! I was just wondering do you have the PiXL GCSE Maths Predicted Paper 2016?
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    (Original post by phat-chewbacca)
    It happens to everyone! I was just wondering do you have the PiXL GCSE Maths Predicted Paper 2016?
    Unfortunately not, sorry!
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    (Original post by Zacken)
    Unfortunately not, sorry!
    No worries, thanks anyway!
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    (Original post by Zacken)
    As above - (I have no clue how this slipped my eye) but the correct answer should be \frac{5(1 - \sqrt{2})}{-1} = \frac{5 - 5\sqrt{2}}{-1} = 5\sqrt{2} - 5, i.e: you need to multiply out the 5(1-\sqrt{2}) as 5 - 5\sqrt{2} and not as 5 - \sqrt{2}.

    http://prntscr.com/axdbp4 ?

    urmm so why don't we multiply the two denominators?
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    (Original post by phat-chewbacca)
    No worries, thanks anyway!
    http://www.mathsgenie.co.uk/resources/june2016p1.pdf

    That what you looking for?

    Sorry if its not
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    (Original post by junayd1998)
    http://prntscr.com/axdbp4 ?

    urmm so why don't we multiply the two denominators?
    You do multiply the two denominators. Your denominators were fine in the previous screenshot. Your numerator wasn't.
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    (Original post by Zacken)
    You do multiply the two denominators. Your denominators were fine in the previous screenshot. Your numerator wasn't.
    http://prntscr.com/axdy3h So that's the final answer?
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    (Original post by junayd1998)
    http://prntscr.com/axdy3h So that's the final answer?
    Indeed.
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    Here is the right answer. https://gyazo.com/31ec0ada59c65f931222e056a681f538
    It said rationalise the denominator so you probably dont need to do the final step
 
 
 
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