Original post by MSI_10
f(x) = (x^2 -4)/3
Find f^-1
Is the answer +/- SQRT(3x+4) ?
Find f^-1
Is the answer +/- SQRT(3x+4) ?
Is there a restriction on the domain of f(x)?
Your answer can't be right if you recall what you know about the definition of a function.
Original post by MSI_10
f(x) = (x^2 -4)/3
Find f^-1
Is the answer +/- SQRT(3x+4) ?
Find f^-1
Is the answer +/- SQRT(3x+4) ?
I think you only want because otherwise the inverse won't be a function.
Original post by Mr M
Is there a restriction on the domain of f(x)?
Your answer can't be right if you recall what you know about the definition of a function.
Your answer can't be right if you recall what you know about the definition of a function.
Ah whoops yeah forgot to include it in Q..
The domain for the original function was less or equal to 0
Original post by MSI_10
Ah whoops yeah forgot to include it in Q..
The domain for the original function was less or equal to 0
The domain for the original function was less or equal to 0
So how should you amend your answer?
Original post by Mr M
So how should you amend your answer?
- SQRT (3x+4) since the range has to be less than or equal to 0 for the inverse function..
Original post by MSI_10
- SQRT (3x+4) since the range has to be less than or equal to 0 for the inverse function..
That's right.
Original post by Mr M
That's right.
Thanks, also, would the range for the original function be less or equal to -4/3?
I input x=o as the domain said that is the highest value it could be into f(x) which gives (0^2 - 4) /3
I got my core 3 paper back and apparently my answer is wrong, rather confused tbf..
Original post by MSI_10
Thanks, also, would the range for the original function be less or equal to -4/3?
No. Can you sketch it?
Original post by Mr M
No. Can you sketch it?
Nope..
So what's the first step to solving for the range? Thought it was to use the value given in the domain..
EDIT: Wait a sec, is the answer more than or equal to -4/3??
(edited 11 years ago)
Original post by MSI_10
Nope..
So what's the first step to solving for the range? Thought it was to use the value given in the domain..
EDIT: Wait a sec, is the answer more than or equal to -4/3??
So what's the first step to solving for the range? Thought it was to use the value given in the domain..
EDIT: Wait a sec, is the answer more than or equal to -4/3??
Yes.
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