C3 expo and log functions help please

Sorry - I'm still confused! I did C1 and C2 around 2008 so not sure if it was in there and I can't remember?


have reviewed the answer to see if that helps, but the working goes to


[In(2x)+1] [3In(2x) -1] [in(2x)-2] and i have no idea how to get from the first equation to the second.

Could you solve

$3y^3 - 4y^2 - 5y + 2 = 0$

I'm still coming up blank! I know I know how to do it, I just can't remember, and I don't have my old books to look it up

Here's a starting point:

Divide the whole thing by ln2x.
Now set ln2x=x and sub x into the equation.
See the quadratic..?

Hope that helps.

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This does not give a quadratic, it is not appropriate advice

Could you solve

$3y^3 - 4y^2 - 5y + 2 = 0$

When you factories the cubic polynomial the equation will be (y-2)(3y-1)(y+1)=0

Which leads to the solution that the OP had seen

so by sub in ln2x for y to solve x. I got x= 3.69, 0.70, 1.36 (to 2.d.p). Is that right?

you can try inputting the cubic equation into your calculator which will solve it for you

WTF how do you do that?????

WTF how do you do that?????