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# AQA Core 2 Logarithms Question watch

1. Hello,

I'm hoping someone can help me, I'm stuck on Q10(f) from Chapter 8 (Exponentials and Logarithms) of the book "Core 2 for AQA" by Cambridge The School Mathematics Project.

10. Solve these equations for x:

(f) 6x-4 = 2x+3

I've done all the other 1 - 14Qs in this exercise, I don't know why I'm struggling with this question so much (though I have been out of education for 4 years so I'm a little rusty!).

Any help would really be appreciated

Thanks
2. I would take the natural logs of both side:

Since ln(6) and ln(2) are constants, this is a linear equation in x in the form ax+b.

Rearrange to find x.
3. What have you tried?

Hint: the chapter is about logs ... how could they help?

SamK - we aren't supposed to post solutions, just hints!
4. (Original post by SamKeene)
I would take the natural logs of both side:

Since ln(6) and ln(2) are constants, this is a linear equation in x in the form ax+b.

Rearrange to find x.
Thank you so much , I made things way too complicated for myself and had gotten in a complete mess.
5. (Original post by Muttley79)
What have you tried?

Hint: the chapter is about logs ... how could they help?

SamK - we aren't supposed to post solutions, just hints!
Oh I know the chapter is about logs, I have completed all the other 13 questions in the exercise, I was just having troubles rearranging this one.
6. (Original post by alyyspp)
Thank you so much , I made things way too complicated for myself and had gotten in a complete mess.
For extra understanding, you might want to do the question without using the natural log. Take log base 6 on the left side, and log base 2 on the right side, then use the log law to change the base of one to be the same as the other, and solve that.
7. (Original post by SamKeene)
For extra understanding, you might want to do the question without using the natural log. Take log base 6 on the left side, and log base 2 on the right side, then use the log law to change the base of one to be the same as the other, and solve that.
Ah ok, that's a good idea, I'll give that a go now. Thank you
8. I'd suggest taking logs (base 10) is a better approach.

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