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Physics maths question

ImageUploadedByStudent Room1421757534.995474.jpg Does anyone know how to solve this?


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Original post by goodwinning
ImageUploadedByStudent Room1421757534.995474.jpg Does anyone know how to solve this?


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4.1 t=3 so v=230(1e0.1×3)v=230(1-e^{-0.1 \times 3}). Calculate that.

4.2 v=200 so 200=230(1e0.1t)200=230(1-e^{-0.1 t}). Solve that.
Reply 2
Original post by BuryMathsTutor
4.1 t=3 so v=230(1e0.1×3)v=230(1-e^{-0.1 \times 3}). Calculate that.

4.2 v=200 so 200=230(1e0.1t)200=230(1-e^{-0.1 t}). Solve that.


Right, I'm alright for 4.1 now but I'm stuck on how to solve for t on the second one.


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Original post by goodwinning
Right, I'm alright for 4.1 now but I'm stuck on how to solve for t on the second one.
You need to rearrange the equation to make t the subject
Reply 4
Ok so I've got 200/230 = 1-e^-0.1t so far, now I have to take the ln right?


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Original post by goodwinning
Ok so I've got 200/230 = 1-e^-0.1t so far, now I have to take the ln right?


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Yes use natural logs on both sides
You shouldn't take natural logs until the equation has e ^ power as a subject
Reply 7
Original post by Muttley79
You shouldn't take natural logs until the equation has e ^ power as a subject


Yeah I figured as I was doing it. So I've now got e^-0.1t = -200/230 +1 and I suppose now I can take natural logs of both sides. Correct?


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How will you deal with the negative power?
Reply 9
Original post by Muttley79
How will you deal with the negative power?


Once I've take natural log of both sides, I'll then multiply both sides by negative 1.


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(edited 9 years ago)
Reply 10


Once I've take natural log of both sides, I'll end up with -0.1t=ln-200/230 + 1 and il divide both sides by -0.1



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