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anyone need help for maths?

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Original post by *SweaterWeather*
uhmmm sorry, but for this question wouldnt the probability be slightly less than that?

If you don't simplify it, just so it's clearer to see:

so 4/10 girls, and 6/10 boys
P(boy) on the first choice = 6/10
but P(boy) on second choice (assuming a boy was chosen the first time) would be 5/9 as one boy has been picked so cannot be picked again?
So the overall probability would be 5/9 x 6/10, which is 1/3 :smile:

Sorry if this is over complicating stuff :frown:


ah yeah you're right, my apologies :smile:
Original post by aadil10
ah yeah you're right, my apologies :smile:


no worries, it confused me slightly as well as it seems so easy at first, until you realise the dependency o.O
Original post by aadil10
f(2x) stretches the graph vertically by twice as much.

2f(x) stretches (or squashes) it by 1/2 horizontally


This is the wrong way round.

Original post by aadil10
Okay so first thing about the probabilities of each one just once.

Add them all together first so 4+6=10 students in the class

this means: 4/10 girls 6/10 boys which you can simplify to 2/5 girls 3/5 boys.

So now you want the probability of getting boys and then boys again.

If it's a probability of something and something else you times them together.

So 3/5 times 3/5 = 9/25




Posted from TSR Mobile
The probability of choosing a boy the first time is 6/10 = 3/5.
The probability of choosing a boy the second time is 5/9, as there are now 5 boys and 9 boys & girls in total.
Therefore the probability of choosing 2 boys at random is 3/5 * 5/9 = 15/45 = 1/3.
Reply 23
Original post by shwansalah
2x squared - 7x+3

FIRST, you do the first number times the end number, ( 2 TIMES 3= 6)

SECONDLY, two numbers that times to make 6 and plus to make -7, the answer is -6 and -1

THRIDLY, the expression was 2x squared -7x + 3,

NOW it becomes 2x squared -6x -1x +3 , ( we split the -7x into -6x and -1x)

NOW we factorise each part seperately


so we first factorise 2x squared -6x which is 2x(x-3)

Then we factorise the -1x + 3 which is -1(x-3)

which becomes (2x-1) and (x-3) which is ur final answer


Yeah this really helped thanks!
Reply 24
Original post by shwansalah
2x squared - 7x+3

FIRST, you do the first number times the end number, ( 2 TIMES 3= 6)

SECONDLY, two numbers that times to make 6 and plus to make -7, the answer is -6 and -1

THRIDLY, the expression was 2x squared -7x + 3,

NOW it becomes 2x squared -6x -1x +3 , ( we split the -7x into -6x and -1x)

NOW we factorise each part seperately


so we first factorise 2x squared -6x which is 2x(x-3)

Then we factorise the -1x + 3 which is -1(x-3)

which becomes (2x-1) and (x-3) which is ur final answer


Wait one question, when you split up the equation into 2 to factorise seperately how do you know which split up part to put with the other? does that make sense? For example with this how would I know to factorise 2x^2-6x and -1x+3 rather than 2x^2-1x and 2x^2-6x
Reply 25
Original post by joe4234
Wait one question, when you split up the equation into 2 to factorise seperately how do you know which split up part to put with the other? does that make sense? For example with this how would I know to factorise 2x^2-6x and -1x+3 rather than 2x^2-1x and 2x^2-6x


basically when you factorise both parts, the bracket has the be the same,, e.g

first part is 2x(x-3) and the other part is -1(x-3) , as you can see the (X-3) IS THE SAME,

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