uhmmm sorry, but for this question wouldnt the probability be slightly less than that?
If you don't simplify it, just so it's clearer to see:
so 4/10 girls, and 6/10 boys P(boy) on the first choice = 6/10 but P(boy) on second choice (assuming a boy was chosen the first time) would be 5/9 as one boy has been picked so cannot be picked again? So the overall probability would be 5/9 x 6/10, which is 1/3
Okay so first thing about the probabilities of each one just once.
Add them all together first so 4+6=10 students in the class
this means: 4/10 girls 6/10 boys which you can simplify to 2/5 girls 3/5 boys.
So now you want the probability of getting boys and then boys again.
If it's a probability of something and something else you times them together.
So 3/5 times 3/5 = 9/25
Posted from TSR Mobile The probability of choosing a boy the first time is 6/10 = 3/5. The probability of choosing a boy the second time is 5/9, as there are now 5 boys and 9 boys & girls in total. Therefore the probability of choosing 2 boys at random is 3/5 * 5/9 = 15/45 = 1/3.
FIRST, you do the first number times the end number, ( 2 TIMES 3= 6)
SECONDLY, two numbers that times to make 6 and plus to make -7, the answer is -6 and -1
THRIDLY, the expression was 2x squared -7x + 3,
NOW it becomes 2x squared -6x -1x +3 , ( we split the -7x into -6x and -1x)
NOW we factorise each part seperately
so we first factorise 2x squared -6x which is 2x(x-3)
Then we factorise the -1x + 3 which is -1(x-3)
which becomes (2x-1) and (x-3) which is ur final answer
Wait one question, when you split up the equation into 2 to factorise seperately how do you know which split up part to put with the other? does that make sense? For example with this how would I know to factorise 2x^2-6x and -1x+3 rather than 2x^2-1x and 2x^2-6x
Wait one question, when you split up the equation into 2 to factorise seperately how do you know which split up part to put with the other? does that make sense? For example with this how would I know to factorise 2x^2-6x and -1x+3 rather than 2x^2-1x and 2x^2-6x
basically when you factorise both parts, the bracket has the be the same,, e.g
first part is 2x(x-3) and the other part is -1(x-3) , as you can see the (X-3) IS THE SAME,