If there are 6 apples and you take away 4, how many do you have?

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10² - 10 - 90 = 0So if Hannah has 10 sweets she has a 6/10 chance of pulling out an orange sweet first time and then a 5/9 chance of pulling one out second time.6/10 X 5/9 = 30/90 or 1/3

Duh

Reply 41

TeeEm

6 apples minus 4
(you cannot subtract 4 from 6 apples)

Reply 42

username1539513

4 apples and some very hard poop

Reply 43

Bulletzone

Questions like this absolutely send my brain cells everywhere.

Reply 44

TheonlyMrsHolmes

lots of applessssssssssssss

Reply 45

LemonadeAspire

Original post by TeeEm

6 apples minus 4
(you cannot subtract 4 from 6 apples)

Smart lol

Reply 46

TeeEm

Original post by LemonadeAspire

Smart lol

I have to have a PhD ...
That was my thesis ... On completion I even called a press conference.

Reply 47

stochasticking

Original post by _icecream

10² - 10 - 90 = 0So if Hannah has 10 sweets she has a 6/10 chance of pulling out an orange sweet first time and then a 5/9 chance of pulling one out second time.6/10 X 5/9 = 30/90 or 1/3

That's trial and error, that's not how you solve the problem. If there are n sweets in a bag, 6 of which are orange then the probability of picking an orange is simply 6/n. To pick another orange sweet would now be 6/n* 5/n-1 because there are now n-1 sweets in the bag and 5 orange sweets and this equals 1/3.
6/n * 5/n-1 =1/3
30/n^2-n=1/3
90/n^2-n=1
90=n^2-n therefore : n^2-n-90=0.