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If there are 6 apples and you take away 4, how many do you have? watch

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    (Original post by _icecream)
    10² - 10 - 90 = 0So if Hannah has 10 sweets she has a 6/10 chance of pulling out an orange sweet first time and then a 5/9 chance of pulling one out second time.6/10 X 5/9 = 30/90 or 1/3
    Duh
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    6 apples minus 4
    (you cannot subtract 4 from 6 apples)
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    4 apples and some very hard poop
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    Questions like this absolutely send my brain cells everywhere.
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    lots of applessssssssssssss
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    (Original post by TeeEm)
    6 apples minus 4
    (you cannot subtract 4 from 6 apples)
    Smart lol
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    (Original post by LemonadeAspire)
    Smart lol
    I have to have a PhD ...
    That was my thesis ... On completion I even called a press conference.
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    (Original post by _icecream)
    10² - 10 - 90 = 0So if Hannah has 10 sweets she has a 6/10 chance of pulling out an orange sweet first time and then a 5/9 chance of pulling one out second time.6/10 X 5/9 = 30/90 or 1/3
    That's trial and error, that's not how you solve the problem. If there are n sweets in a bag, 6 of which are orange then the probability of picking an orange is simply 6/n. To pick another orange sweet would now be 6/n* 5/n-1 because there are now n-1 sweets in the bag and 5 orange sweets and this equals 1/3.
    6/n * 5/n-1 =1/3
    30/n^2-n=1/3
    90/n^2-n=1
    90=n^2-n therefore : n^2-n-90=0.
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    A police caution for petty theft?
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    4 apples
 
 
 
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