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Exponential graph GCSE past papers question

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I'm having some trouble with the question in the picture. I used some trial and error to find an answer, but I'm sure there must be another way of doing it. Any ideas? Thanks.
Reply 1
You have two points, let's use the first one: 5=pq5 = pq and 320=pq4=pqq3=5q3q3=320 = pq^4 = pqq^3 = 5q^3 \Rightarrow q^3 = \cdots.
Reply 2
Original post by Zacken
You have two points, let's use the first one: 5=pq5 = pq and 320=pq4=pqq3=5q3q3=320 = pq^4 = pqq^3 = 5q^3 \Rightarrow q^3 = \cdots.


Thanks! I've worked it out now using that to form the equation 320/q^3=5 and solving it.
Reply 3
Original post by Lelanor
Thanks! I've worked it out now using that to form the equation 320/q^3=5.


Do you mean q3=3205=64=43\displaystyle q^3 = \frac{320}{5} = 64 = 4^3?
Reply 4
Original post by Zacken
Do you mean q3=3205=64=43\displaystyle q^3 = \frac{320}{5} = 64 = 4^3?


Well, I did this:
320/q^3 = 5
320 = 5q^3
q^3 = 64
q = 4
But that's pretty much the same thing.
Reply 5
Original post by Lelanor
Well, I did this:
320/q^3 = 5
320 = 5q^3
q^3 = 64
q = 4
But that's pretty much the same thing.


Fair enough. You cool with the method?
Reply 6
Original post by Zacken
Fair enough. You cool with the method?


Yep, your first post nudged me in the right direction. I realised I'd have to form some kind of equation(s) but I just couldn't work out what, so thanks :smile:
Reply 7
Original post by Lelanor
Yep, your first post nudged me in the right direction. I realised I'd have to form some kind of equation(s) but I just couldn't work out what, so thanks :smile:


Awesome, glad I helped.

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