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    Find dx
    dy

    y = 2X^3 - 3X^2 + 4X - 6

    Also, am I the only one who really enjoys surds ?

    Yes I know these aren't surds, inb4 so [email protected] says it. Thanks for the help, will loiter to pay it forward.
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    (Original post by HanSoloLuck)
    Find dx
    dy

    y = 2X^3 - 3X^2 + 4X - 6

    Also, am I the only one who really enjoys surds ?

    Yes I know these aren't surds, inb4 so [email protected] says it. Thanks for the help, will loiter to pay it forward.
    What's the issue? It's a simple case of differentiating each term carefully by using the rule that differentiating ax^n gives anx^(n-1).
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    Firstly I think you mean dy/dx

    and secondly like the person above me said what's the issue ?

    dy/dx = 6X^2 - 6X + 4
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    (Original post by Shoot)
    Firstly I think you mean dy/dx

    and secondly like the person above me said what's the issue ?

    dy/dx = 6X^2 - 6X + 4
    Nope, i don't get it. I know it's something incredibly dumb that I'm missing, but, I can no brain that at the moment.
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    (Original post by HanSoloLuck)
    Nope, i don't get it. I know it's something incredibly dumb that I'm missing, but, I can no brain that at the moment.
    Saying "i don't get it" is extremely useless. What particular bit don't you get? What's the issue? What have you tried?
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    (Original post by HanSoloLuck)
    Nope, i don't get it. I know it's something incredibly dumb that I'm missing, but, I can no brain that at the moment.
    Don't worry man I got you on this,

    basically what I did was the differentiation rule ( you can take all the values out separately if it makes it easier for you to understand)

    So the f(x) = 2X^3 - 3X^2 + 4X - 6

    So you have the value of 2X^3, - 3X^2 , 4X and - 6

    Now what you basically do is times the indices to the coefficient

    so in this case I did 2 x 3, 3 x 2 and 4 x 1 ( I ignore the 6 as it doesn't have a variable and isn't a coefficient )

    Then once I do that I subtract the indices by -1 so the ^3 becomes ^2, the ^2 (on 3X) becomes ^1 (so just X) and the X is removed from the 4X as it was basically (4X^1)

    So my answer then is dy/dx = dy/dx = 6X^2 - 6X + 4
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    (Original post by Zacken)
    Saying "i don't get it" is extremely useless. What particular bit don't you get? What's the issue? What have you tried?
    I like your enthusiasm to want to help, it's a little creepy but kinda nice. Didn't realize what it was asking me/was trying to do something else entirely without realizing.

    (Original post by Shoot)
    Don't worry man I got you on this,

    basically what I did was the differentiation rule ( you can take all the values out separately if it makes it easier for you to understand)

    So the f(x) = 2X^3 - 3X^2 + 4X - 6

    So you have the value of 2X^3, - 3X^2 , 4X and - 6

    Now what you basically do is times the indices to the coefficient

    so in this case I did 2 x 3, 3 x 2 and 4 x 1 ( I ignore the 6 as it doesn't have a variable and isn't a coefficient )

    Then once I do that I subtract the indices by -1 so the ^3 becomes ^2, the ^2 (on 3X) becomes ^1 (so just X) and the X is removed from the 4X as it was basically (4X^1)

    So my answer then is dy/dx = dy/dx = 6X^2 - 6X + 4
    Yep thanks, simple to do, as said above, I was trying to do something else entirely. I'll bring my crayons to the exam I guess, wont even use them to draw, just jam them up my nose........ over tired.
 
 
 
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