CCEA M1 Mechanics 25th May 2016

On the whole I think that went pretty well; the last 2 Q6 and Q7 were decently tricky, but could have been a lot worse based on previous past papers.

On the whole, I think that went well; nothing that was impossible!

Reply 21

Bclare163

What did you get for 7? I got 1.37 m

Reply 22

studentdream

I got 0.3... As the answer to acceleration in question 6, I feel like that is wrong ahha I found it hard but doable

Reply 23

Hussxni19

4

Original post by Bclare163

how did everyone find it ? and does anyone have the paper/unofficial mark scheme

It was actually difficult compared to all the past papers. Think I failed it ngl

Reply 24

student349

Can someone explain how they did the ladders question. Im normally ok with ladders but I found this one so confusing and ended up with an answer larger than the ladder after writing a bulls**t method to get method marks.

Reply 25

Bclare163

Basically I let F = coefficient x R. And then I took moments from A, letting the distance the man climb be x. I got 1.37 but I'm not sure if that's right

Original post by student349

Can someone explain how they did the ladders question. Im normally ok with ladders but I found this one so confusing and ended up with an answer larger than the ladder after writing a bulls**t method to get method marks.

Reply 26

John5678

1

Original post by Bclare163

What did you get for 7? I got 1.37 m

Yes I did

Original post by student349

Can someone explain how they did the ladders question. Im normally ok with ladders but I found this one so confusing and ended up with an answer larger than the ladder after writing a bulls**t method to get method marks.

Can you remember the wording of the question, and I can show you then!

Reply 27

John5678

1

Original post by student349

Can someone explain how they did the ladders question. Im normally ok with ladders but I found this one so confusing and ended up with an answer larger than the ladder after writing a bulls**t method to get method marks.

When you resolved horizontally you got the reaction at B= friction
When you resolved vertically you got the reaction at A= 20g+70g

Then when you resolved everything parallel/ perpendicular to the plane; you took moments about A,
(20gcos65 x 1) + (70gcos65 x x) = RBsin65

From that, you then worked our Rb, equalling friction as you could work out the reaction at A, and then x was the distance from A that the 70kg was.

Hope that helped!

Reply 28

ozmo19

16

What did you all get for Q2 (displacement time graph)?
I got;
5 m/s
Displacement= -280
Avrg speed= 4.74 m/s

Q4
Times at rest; 2s and 10s
And the distance travelled between 0s and 10s= 104m?

Anyone get these or different?

Reply 29

John5678

1

Original post by ozmo19

What did you all get for Q2 (displacement time graph)?
I got;
5 m/s
Displacement= -280
Avrg speed= 4.74 m/s

Q4
Times at rest; 2s and 10s
And the distance travelled between 0s and 10s= 104m?

Anyone get these or different?

For that d/t graph, was it distance or displacement they were looking for?

Not sure about my Q4 answer

Reply 30

ozmo19

16

Original post by John5678

For that d/t graph, was it distance or displacement they were looking for?

Not sure about my Q4 answer

They asked for displacement. Did you get 280 anyway?

(edited 7 years ago)

Reply 31

Xsk

4

I understood the pulleys question fine, but I mucked it up the answers majorly somehow... Hoping it was just a calculation error and that I wont be punished too harshly for it...

Reply 32

student349

Original post by John5678

When you resolved horizontally you got the reaction at B= friction
When you resolved vertically you got the reaction at A= 20g+70g

Then when you resolved everything parallel/ perpendicular to the plane; you took moments about A,
(20gcos65 x 1) + (70gcos65 x x) = RBsin65

From that, you then worked our Rb, equalling friction as you could work out the reaction at A, and then x was the distance from A that the 70kg was.

Hope that helped!

Thanks. I was running out of time and I just put as much relevant info as possible on the page. Ill be lucky to get 3 or 4 method marks :s-smilie:

Reply 33

PenguinEmperor

15

Ah I did RB instead of RBsin65, ah well that is only a mark lost hopefully. I ended up with 1.42 instead :frown:

Reply 34

Ccc3399

Are there any unofficial mark schemes for the paper yet?

Reply 35

John5678

1

Original post by ozmo19

They asked for displacement. Did you get 280 anyway?

Must of read the question wrong; I got 1480, as I took it to be distance travelled [600+600+280] Hopefully I didn't lose too many marks!

Reply 36

studentdream

Original post by John5678

Must of read the question wrong; I got 1480, as I took it to be distance travelled [600+600+280] Hopefully I didn't lose too many marks!

I did that too.. I'm pretty sure it did ask it?? It asked for the displacement of D and then the total distance traveled

Reply 37

scomiskey872

Original post by John5678

Must of read the question wrong; I got 1480, as I took it to be distance travelled [600+600+280] Hopefully I didn't lose too many marks!

I got the same as you, I thought it said distance...

Reply 38

Sparklez10

2

Original post by ozmo19

What did you all get for Q2 (displacement time graph)?
I got;
5 m/s
Displacement= -280
Avrg speed= 4.74 m/s

Q4
Times at rest; 2s and 10s
And the distance travelled between 0s and 10s= 104m?

Anyone get these or different?

I got the same as you for qu2!!
Qu 4 for total distance travelled I got 62.4m I think!! :frown:

But got 2 and 10!

Reply 39

ozmo19

16

Original post by studentdream

I did that too.. I'm pretty sure it did ask it?? It asked for the displacement of D and then the total distance traveled

Original post by scomiskey872

I got the same as you, I thought it said distance...

"The cyclist maintains a constant velocity as he travels from B to D.
Find the displacement of D from O. [4]
Find the cyclist's average speed for the whole journey. [3]"

Didn't ask anything about distance or total distance.

CCEA M1 Mechanics 25th May 2016

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