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How to create a short sequence with random numbers in python?

How do you generate a short sequence of random numbers and allocate it to the user on python. Like say if they input the question 'How do i fix my computer?' , they should be given a unique id and they will basically be given a case number which will then be sent off to a technician.

How would I code this with python??

Would anyone be able to give an example please?????

Thanks

bump

If you want a case number that is (somewhat) easy to remember or communicate verbally then you should look at the random module, however depending on how large a number you generate and how long you will be generating numbers for it would be possible to eventually get a conflict of duplicate numbers (so you would have to keep track of previous numbers and if you get one again regenerate), if you don't care about readability and don't want to keep track of previous id's then using the uuid module would be better and drastically lower the probability of getting a duplicate id.

>>> import uuid
>>> str(uuid.uuid4())
'c5227b41-8331-46be-935f-5acdb9662b57'
>>> str(uuid.uuid4())
'213b0409-c051-4f04-a3ac-af8be4d7977e'
>>> str(uuid.uuid4())
'a1fbeb4f-f901-425d-a15a-5f65c64e7b0a'
>>> str(uuid.uuid4())
'7e23039e-7035-4afc-adf1-7a995da7bdf7'
>>> str(uuid.uuid4())
'744ba11e-d379-4368-84bb-c8ab2eebdb8b'
>>> str(uuid.uuid4())
'b5e888d9-2fe4-4172-bcc6-e2a1d656161a'
>>> str(uuid.uuid4())
'a410e726-3b5b-48a1-a44a-df38f6cafdef'
>>> str(uuid.uuid4())
'175d5669-3480-4c67-8113-95cd2f9ff393'
>>> str(uuid.uuid4())
'078b9e59-74e6-402b-b7f1-5b2ace959bfd'
>>> str(uuid.uuid4())
'ab43b628-65be-4c51-b6c0-afc7141d84c8'

(edited 7 years ago)

Reply 3

shinebrighterx

Original post by bluepearl7

With the use of variables and random.randint.
Assign the list of random numbers to a new variable.

http://stackoverflow.com/questions/22842289/python-generate-n-unique-random-numbers-within-a-range

Reply 4

2190243

from random import randint #imports relevant libraries

caseNumber = (randint(1,100)) * 12345#defines caseNumber to equal a random number, multiplies that number by 12345 so it is a long number
print (caseNumber)

That will work, but it's definitely not the best way to do it

Reply 5

Vyres

Very nice and simple way to get a 5 figure number everytime

from random import randint

total = ''
for i in range (5):
    x = randint(1,9)
    total = total + ''.join(str(x))
print (total)

(edited 7 years ago)

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