Phosphorus reacts with iodine to produce phosphorus(III) iodide:
P4 + 6I2 → 4PI3
What is the minimum mass of iodine required to produce 1 kg of phosphorus(III) iodide
when the phosphorus is in excess?
Data: molar mass of phosphorus(III) iodide = 411.7gmol−1
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Edexcel Chemistry Question 2018 Jan watch
- Thread Starter
- 02-03-2018 11:34
- 02-03-2018 12:46
Calculate the moles of PI3. The moles of iodine is 6/4 that amount.
Then calculate the molar mass of I2 (twice the mass of an iodine atom) and its mass.
The answer is 924.70 g = 0.925 kg (B)
Where did you find this anyway? Isn't the paper locked?