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ALEVEL chemistry help

bromomethane with excess ammonia
b)chloroethane with ammonia (1:1 ratio)
c)bromomethane with aminoethane (1:1)
I don’t understand why it’s (1:1ratio) I always thought it was 1:2 ratio can someone give me the equation for b and c pls

Reply 1

samhodg222

Original post by Sharemine

im pretty sure in this case 1:1 ratio will simply mean there is equal amounts of both reactants

Reply 2

Pigster

Original post by Sharemine

I don’t understand why it’s (1:1ratio) I always thought it was 1:2 ratio can someone give me the equation for b and c pls

An excess of the haloalkane will lead to the formation of secondary (and then tertiary) amines. If you know/understand the mechanism, you will see that, just like the reactant, the amine product still has a lone pair on the N. In fact the product is a better nucleophile than the initial reactant.