so u have to use the formula of mass=mr x moles , 1)you know that mass of copper oxide is 79.5 g and you can work out Mr from periodic table for CuO which is 79.5. then using mass mr moles euqation , find moles by doing 79.5/79.5 which gets you 1 mole
2) as copper oxide and copper is 1:1 ratio (as it is already balances and there are no big numbers) the moles will be the same for Cu
3) You can work out Nr for Cu from periodic table which is 63.5 and the moles will be same as CuO which is 1 mole. now using moles mass mr equation again, do 63.5x1 which gives the answer of 63.5g
so u have to use the formula of mass=mr x moles , 1)you know that mass of copper oxide is 79.5 g and you can work out Mr from periodic table for CuO which is 79.5. then using mass mr moles euqation , find moles by doing 79.5/79.5 which gets you 1 mole
2) as copper oxide and copper is 1:1 ratio (as it is already balances and there are no big numbers) the moles will be the same for Cu
3) You can work out Nr for Cu from periodic table which is 63.5 and the moles will be same as CuO which is 1 mole. now using moles mass mr equation again, do 63.5x1 which gives the answer of 63.5g