A the weaker acid.
B the stronger oxidising agent.
C the weaker oxidising agent.
D the stronger reducing agent.(Total 1 mark)
I think it’s C, because iodine in NaI has an oxidation state of -1, in HI it’s still -1, but in I2 it’s 0, meaning sulfuric acid is the weaker oxidising agent as its unable to oxidise and increase the oxidation state of the iodine. Anyone else who reads this please correct me if I’m wrong x