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Invariant points and lines of a matrix

How do you find the invariant points of a matrix?
I've got the matrix
( 3 2)
( 1 2)
(2x2 matrix rows 32 and 12)
And I think one of the invariant lines is y=-x
Is this right and are there any others?
(edited 4 years ago)
Original post by Student135246
How do you find the invariant points of a matrix?
I've got the matrix
( 3 2)
( 1 2)
(2x2 matrix rows 32 and 12)
And I think one of the invariant lines is y=-x
Is this right and are there any others?


Do you know the difference between different lines and invariant points?
Original post by ThiagoBrigido
Do you know the difference between different lines and invariant points?

i think invariant points are points that map onto themselves
invariant lines are lines where any point on that line will be mapped onto the line
is this right?
Original post by Student135246
How do you find the invariant points of a matrix?
I've got the matrix
( 3 2)
( 1 2)
(2x2 matrix rows 32 and 12)
And I think one of the invariant lines is y=-x
Is this right and are there any others?


Let's check, if I take any point on the line y=xy=-x and apply the matrix to it, I should get back to the original point, i.e.

(3212)(xx)=(xx)\begin{pmatrix} 3 & 2 \\ 1 & 2 \end{pmatrix} \begin{pmatrix} x \\ -x \end{pmatrix} = \begin{pmatrix} x \\ -x \end{pmatrix}

must be satisfied. Which it is, just check by expanding the LHS.



Generally, you find invariant lines by seeking them in the form y=mxy=mx and determining what mm must be.

Imposing this, you simply need to solve;

(3212)(xmx)=(xmx)\begin{pmatrix} 3 & 2 \\ 1 & 2 \end{pmatrix} \begin{pmatrix} x \\ mx \end{pmatrix} = \begin{pmatrix} x \\ mx \end{pmatrix}

Expanding the top row;

3x+2mx=x    (2+2m)x=0    m=13x + 2mx = x \implies (2+2m)x = 0 \implies m = -1

and this is the ONLY line, because there are not other solutions to this equation. You can check that this satisfies the expansion of the bottom row;

x+2mx=mxx + 2mx = mx

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