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The train leaves station A from rest with a constant acceleration of 0.2ms^-2 it reaches its maximum speed after 2mins maintains this speed for 4min then slows down to stop at station B with acceleration 1.5ms^-2. Calculate the distance from A to B.
Reply 1
Original post by Salimaaaa
The train leaves station A from rest with a constant acceleration of 0.2ms^-2 it reaches its maximum speed after 2mins maintains this speed for 4min then slows down to stop at station B with acceleration 1.5ms^-2. Calculate the distance from A to B.

Have you tried anything? Where are you stuck?
Original post by Notnek
Have you tried anything? Where are you stuck?


With the whole question tbh I don’t know where to start
Reply 3
Original post by Salimaaaa
With the whole question tbh I don’t know where to start

Try drawing a speed-time graph.
7E6C26C1-68A7-4CE0-9BC5-7A66D9F6E253.jpegDistance is area under the graph so what would u do
Original post by Notnek
Try drawing a speed-time graph.
Original post by cregsim
Is that a real task

Idk it’s a question
Reply 6
Original post by Salimaaaa
7E6C26C1-68A7-4CE0-9BC5-7A66D9F6E253.jpegDistance is area under the graph so what would u do

You need a speed-time graph, not an acceleration-time graph.

So for the first stage of the journey, if the train accelerates for 2 mins (120 seconds) at 0.2m/s^2, what speed does it reach? Label that on the y-axis.

Then you need to find the area under the graph like you said, which is just the area of a trapezium.

(Alternatively you could do this whole question just with SUVAT but a common approach to something like this is to use a speed-time graph.)

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