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help
Make a balanced symbol equation, using the data from this experiment.
Reactants
CaCl2= 666g
Products
Ca = 240g
Cl2= 426g
Reactants
CaCl2= 666g
Products
Ca = 240g
Cl2= 426g
Reply 1
13
calcium: 240/40.1 = 5.985 = 6 mol
chlorine: 426/(35.5x2) = 6 mol
mole ratio of Ca(s) and Cl2(g) = 6:6 = 1:1
so the empirical formula of calcium chloride reactant is CaCl2
chlorine: 426/(35.5x2) = 6 mol
mole ratio of Ca(s) and Cl2(g) = 6:6 = 1:1
so the empirical formula of calcium chloride reactant is CaCl2
(edited 1 year ago)
Reply 2
16
I'm still confused
Reply 3
Reply 4
16
Original post by TheGingerCarrot
OMG, that makes soooo much more sense now. I wasn't sure what they were asking me to do thank you!!!!
Reply 5
Original post by Blackrose06
OMG, that makes soooo much more sense now. I wasn't sure what they were asking me to do thank you!!!!
Ohhhhhhh I've just read that back and you state the reactant is CaCl2 and the products are Ca and Cl2, the Math is correct but it's for the decomposition of CaCl2 so equation is actually the reverse. I always misread when I did my A-level Chem questions and I still do to this day
6Cacl2 --> 6Ca + 6Cl2
(edited 1 year ago)
Reply 6
16
Original post by TheGingerCarrot
Ohhhhhhh I've just read that back and you state the reactant is CaCl2 and the products are Ca and Cl2, the Math is correct but it's for the decomposition of CaCl2 so equation is actually the reverse. I always misread when I did my A-level Chem questions and I still do to this day
6Cacl2 --> 6Ca + 6Cl2
6Cacl2 --> 6Ca + 6Cl2
I got that, so I changed it round anyway
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