Help on maths question

Hi, I'm struggling with this question and cannot find any working out online.

Simplify (3x ^ 9 + 3/8 * x ^ 9) ^ (- 1/3)

The solution is meant to be 2/(3x^3) and I don't understand how you can get to this answer.

Thanks for any help :smile:

Reply 1

tesss5

5

Original post by SamsSide

Hi, I'm struggling with this question and cannot find any working out online.

Simplify (3x ^ 9 + 3/8 * x ^ 9) ^ (- 1/3)

The solution is meant to be 2/(3x^3) and I don't understand how you can get to this answer.

Thanks for any help :smile:

Hello, I've attached the working out here (I think). Let me know if you need any steps explained :smile:

Reply 2

tesss5

5

Original post by SamsSide

Hi, I'm struggling with this question and cannot find any working out online.

Simplify (3x ^ 9 + 3/8 * x ^ 9) ^ (- 1/3)

The solution is meant to be 2/(3x^3) and I don't understand how you can get to this answer.

Thanks for any help :smile:

Sorry, it didn't upload. I'll write it here.
first add whats in the brackets to make (27/8(x^9)]^-1/3
then transform it into the form where instead of it having a negative fractional power, it is 1/(cube root of (27/8(x^9))
Then, cube root it. this gives us 1/[(3x^3)/2]
this is the same as 2/(3x^3)
hope this helps!

Reply 3

SamsSide

OP

3

Original post by tesss5

Sorry, it didn't upload. I'll write it here.
first add whats in the brackets to make (27/8(x^9)]^-1/3
then transform it into the form where instead of it having a negative fractional power, it is 1/(cube root of (27/8(x^9))
Then, cube root it. this gives us 1/[(3x^3)/2]
this is the same as 2/(3x^3)
hope this helps!

Thank you for the help! :smile:

Reply 4

davros

16