Chem question
3.528 g of a group 2 metal M is reacted with an excess of chlorine, the reaction forms 9.775 g of a chloride what is metal M?
Original post by ihaveno name
3.528 g of a group 2 metal M is reacted with an excess of chlorine, the reaction forms 9.775 g of a chloride what is metal M?
If it’s a group 2 metal, then you would expect the formula to be MCl2.
So therefore, can you work out the mass of chloride ions in the product and then use that to work out the moles of chloride ions in the product?
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