Hi can someone help me with this question? I got M = 0.77 but apparently it's wrong
A uniform rod AB rests horizontally on two smooth pivots at the points A and C. The rod is of length 5m and mass 12kg. The distance BC is 1.5m. A mass of Mkg is attached to the rod at B so that the rod remains horizontal and in equilibrium. The reaction at the pivot at C is three times the reaction at the pivot at A. By taking moments around B, it can be shown that the reaction at A is 31.58N. Calculate the value of M.